C# 如何在字符串中查找所有匹配项

假设我有以下字符串：

xx#a#11#yyy#bb#2#z

我正在尝试检索所有出现的

###某物#某物####

（在我的字符串中，我希望有两个匹配项：

##a#11##

和

##bb#2##

）

我尝试使用

Regex.Matches(MyString, ".*(##.*#.*##).*")

但它检索一个匹配项，即整行

---

如何从该字符串中获取所有匹配项？谢谢。

因为在图案的开头和结尾都有

*

，所以只能得到整行匹配。此外，模式中介于

#

之间的

*

太贪婪了，当在一行中遇到时，会将所有预期的匹配项抓取为一个匹配项

你可以用

var results = Regex.Matches(MyString, "##[^#]*#[^#]*##")
    .Cast<Match>()
    .Select(m => m.Value)
    .ToList();

Regex.Matches（MyString，“（##[^#]+#[^#]+#+）”

---

描述

1st Capturing Group (##[^#]+#[^#]+##)
    ## matches the characters ## literally (case sensitive)
    Match a single character not present in the list below [^#]+
        + Quantifier — Matches between one and unlimited times, as many times as possible, giving back as needed (greedy)
    # matches the character # literally (case sensitive)
    # matches the character # literally (case sensitive)
    Match a single character not present in the list below [^#]+
        + Quantifier — Matches between one and unlimited times, as many times as possible, giving back as needed (greedy)
    # matches the character # literally (case sensitive)
    ## matches the characters ## literally (case sensitive)

---

与*的问题是它将匹配

。

@abc123：这取决于需求，然后可以将

*

替换为

+

。我添加了更多的调整选项作为注释。谢谢：）根据您的帮助，我还设法在不使用封闭的###的情况下获得匹配项（即获得a#1而不是##a###）。我使用了这种模式：[^##][^#]*.[^#]*[^#].[^##].[^##].[^##].[^##].[^##].]但接下来您将使用一个捕获组，让我演示一下。

(##[^#]+#[^#]+##)

1st Capturing Group (##[^#]+#[^#]+##)
    ## matches the characters ## literally (case sensitive)
    Match a single character not present in the list below [^#]+
        + Quantifier — Matches between one and unlimited times, as many times as possible, giving back as needed (greedy)
    # matches the character # literally (case sensitive)
    # matches the character # literally (case sensitive)
    Match a single character not present in the list below [^#]+
        + Quantifier — Matches between one and unlimited times, as many times as possible, giving back as needed (greedy)
    # matches the character # literally (case sensitive)
    ## matches the characters ## literally (case sensitive)