C# 如何按名称获取存储在字符串变量中的XAML元素？

例如，我有一个UIElement：

<TextBlock Name="sometextblock" Text="sample text"/>

如何使用此变量获取此元素？我需要访问元素的属性，例如，我需要能够更改文本属性

如何做到这一点

---

谢谢大家!

您可以使用以下方法：

var textBlock = FindChild<TextBlock>(Application.Current.RootVisual, "sometextblock");

    public static bool FindVisualChildByName<T>(this DependencyObject parent, string name, out T control) where T : DependencyObject
    {
        if (parent == null)
            throw new ArgumentNullException(nameof(parent), "Control cấp cha không được null.");

        if (string.IsNullOrWhiteSpace(name))
            throw new ArgumentNullException(nameof(name), "Tên của control cần tìm không được null hoặc empty.");

        var childrenCount = VisualTreeHelper.GetChildrenCount(parent);

        for (var i = 0; i < childrenCount; i++)
        {
            var child       = VisualTreeHelper.GetChild(parent, i);
            var controlName = child.GetValue(FrameworkElement.NameProperty) as string;

            if (controlName == name)
            {
                control = child as T;
                return true;
            }
            if (FindVisualChildByName(child, name, out control)) return true;
        }
        control = null;
        return false;
    }

var textBlock=FindChild（Application.Current.RootVisual，“sometextblock”）；

FindChild方法是：

public static T FindChild<T>(DependencyObject parent, string childName)
        where T : DependencyObject
    {
        // Confirm parent and childName are valid. 
        if (parent == null)
        {
            return null;
        }

        T foundChild = null;

        int childrenCount = VisualTreeHelper.GetChildrenCount(parent);
        for (int i = 0; i < childrenCount; i++)
        {
            DependencyObject child = VisualTreeHelper.GetChild(parent, i);
            // If the child is not of the request child type child
            var childType = child as T;
            if (childType == null)
            {
                // recursively drill down the tree
                foundChild = FindChild<T>(child, childName);

                // If the child is found, break so we do not overwrite the found child. 
                if (foundChild != null)
                {
                    break;
                }
            }
            else if (!string.IsNullOrEmpty(childName))
            {
                var frameworkElement = child as FrameworkElement;
                // If the child's name is set for search
                if (frameworkElement != null && frameworkElement.Name == childName)
                {
                    // if the child's name is of the request name
                    foundChild = (T) child;
                    break;
                }

                // Need this in case the element we want is nested
                // in another element of the same type
                foundChild = FindChild<T>(child, childName);
            }
            else
            {
                // child element found.
                foundChild = (T) child;
                break;
            }
        }

        return foundChild;
    }
}

public static T FindChild（DependencyObject父对象，字符串childName）
其中T:DependencyObject
{
//确认父项和子项名称有效。
如果（父项==null）
{
返回null；
}
T foundChild=null；
int childrenCount=visualtreeheloper.GetChildrenCount（父级）；
for（int i=0；i

如果您在XAML中对元素进行了如下命名：

<TextBlock x:Name="sometextblock" />

---

假设您在XAML上有此功能：

<Button Name="MyButton1" .../>
<Button Name="MyButton2" .../>
<Image Name="MyImage1" .../>
<TextBox Name="MyTextBox1" .../>
<TextBox Name="MyTextBox2" .../>
<Button Name="MyButton3" .../>

然后可以迭代控件并访问属性：

for (int i = 0; i < NameControls.Length; i++)
{
    dynamic MyControl = this.FindName(NameControls[i]);
    // do something
}

---

您可以参考此方法：

var textBlock = FindChild<TextBlock>(Application.Current.RootVisual, "sometextblock");

    public static bool FindVisualChildByName<T>(this DependencyObject parent, string name, out T control) where T : DependencyObject
    {
        if (parent == null)
            throw new ArgumentNullException(nameof(parent), "Control cấp cha không được null.");

        if (string.IsNullOrWhiteSpace(name))
            throw new ArgumentNullException(nameof(name), "Tên của control cần tìm không được null hoặc empty.");

        var childrenCount = VisualTreeHelper.GetChildrenCount(parent);

        for (var i = 0; i < childrenCount; i++)
        {
            var child       = VisualTreeHelper.GetChild(parent, i);
            var controlName = child.GetValue(FrameworkElement.NameProperty) as string;

            if (controlName == name)
            {
                control = child as T;
                return true;
            }
            if (FindVisualChildByName(child, name, out control)) return true;
        }
        control = null;
        return false;
    }

public static bool FindVisualChildByName（此DependencyObject父对象，字符串名称，不受控制），其中T:DependencyObject
{
如果（父项==null）
抛出新ArgumentNullException（nameof（parent），“控件c”ấp cha khđongưược无效。”）；
if（string.IsNullOrWhiteSpace（name））
抛出新ArgumentNullException（nameof（name），“Tên của对照组cần tìm khđngượ何志平ặc空。”）；
var childrenCount=visualtreeheloper.GetChildrenCount（父级）；
对于（变量i=0；i

还有更简单的方法吗？

dynamic MyControl = this.FindName(NameControls[i]);
MyControl.Opacity = 0.7;

    public static bool FindVisualChildByName<T>(this DependencyObject parent, string name, out T control) where T : DependencyObject
    {
        if (parent == null)
            throw new ArgumentNullException(nameof(parent), "Control cấp cha không được null.");

        if (string.IsNullOrWhiteSpace(name))
            throw new ArgumentNullException(nameof(name), "Tên của control cần tìm không được null hoặc empty.");

        var childrenCount = VisualTreeHelper.GetChildrenCount(parent);

        for (var i = 0; i < childrenCount; i++)
        {
            var child       = VisualTreeHelper.GetChild(parent, i);
            var controlName = child.GetValue(FrameworkElement.NameProperty) as string;

            if (controlName == name)
            {
                control = child as T;
                return true;
            }
            if (FindVisualChildByName(child, name, out control)) return true;
        }
        control = null;
        return false;
    }