C# 如何使此代码正常工作？

因此，我最近一直在学习如何制作一个C#应用程序，通过LAMP服务器发送和接收参数，但我似乎遇到了麻烦，我需要一些帮助来了解我在这里做错了什么

这是一个简单的测试应用程序，它向php文件发送两个参数（登录名和密码），并根据参数是否正确接收响应

private void btEntrar_Click(object sender, EventArgs e)
    {
        String login, senha, postData, requestMethod = "POST", contentType = "application/x-www-form-urlencoded", responseFromServer = null;
        String urlLogin = "http://192.168.1.107/knowledgems/accounts/login.php";

        login = tbLogin.Text;
        senha = tbSenha.Text;
        postData = "param1=" + login + "&param2=" + senha;
        byte[] byteArray = Encoding.UTF8.GetBytes(postData);
        WebRequest request = WebRequest.Create(urlLogin);
        WebResponse response;
        Stream dataStream;
        StreamReader reader;

        //Send request
        request.Method = requestMethod;
        request.ContentType = contentType;
        request.ContentLength = byteArray.Length;
        dataStream = request.GetRequestStream();
        dataStream.Write(byteArray, 0, byteArray.Length);
        dataStream.Close();

        //Get response
        response = request.GetResponse();
        dataStream = response.GetResponseStream();
        reader = new StreamReader(dataStream);
        responseFromServer = reader.ReadToEnd();
        reader.Close();
        dataStream.Close();
        response.Close();

        if (responseFromServer.Equals("SUCCESS"))
            MessageBox.Show("Login efetuado.");
        else
            MessageBox.Show("Login não efetuado." + responseFromServer);
    } //btEntrar

虽然一切看起来都是正确的，实际上我可以从我的php文件中得到一个响应，但最后我无法通过验证函数

(if (responseFromServer.Equals("SUCCESS"))) 

尽管显示的响应正好是字符串“SUCCESS”，但我似乎无法将responseFromServer字符串与“SUCCESS”进行比较，以检查登录是否一切正常，因此它总是读取else条件

下面我还发布了我的php文件

<?php
require_once 'connection.php';
header('Content-Type: application/form-data');

class User {
    private $db;
    private $connection;

    function __construct(){
        $this->db = new DB_Connection();
        $this->connection = $this->db->get_connection();            
    } //__construct

    public function does_user_exist($username,$password){
        $query = "SELECT * FROM users WHERE user_username = '$username' AND user_password = '$password'";
        $result = mysqli_query($this->connection,$query);
        if(mysqli_num_rows($result) > 0){
            echo "SUCCESS";     
        } //if
        else {
            echo "ERRO&101";            
        } //else            
        mysqli_close($this->connection);
    } //does_user_exist     

} //class

$user = new User();
if (isset($_POST['param1'],$_POST['param2'])){
    $username = $_POST['param1'];
    $password = $_POST['param2'];
    if(!empty($username) && !empty($password)){
        //$encrypted_password = md5($password);
        $user -> does_user_exist($username,$password);
    }
    else {
        echo "ERRO&100";
    } //else
} //if
?>

“成功”的结尾会有新意吗？看看这是否有效：

if (responseFromServer.Trim().Equals("SUCCESS"))
{

如果回答有新行或什么的怎么办；这有用吗：
responseFromServer.Trim（）.Equals（“SUCCESS”）
？@EdPlunkett我真不敢相信这么简单的事情解决了我的问题。我想我真丢脸，谢谢你马上解决！这就是为什么检查十六进制数据（字符串等）很重要的原因。