C# 用两个相等的值序列化标志枚举
我想定义如下所示的标志枚举:C# 用两个相等的值序列化标志枚举,c#,serialization,enums,xmlserializer,enum-flags,C#,Serialization,Enums,Xmlserializer,Enum Flags,我想定义如下所示的标志枚举: [Flags] [Serializable] public enum Numbers { [XmlEnum(Name = "One")] One = 0x1, [XmlEnum(Name = "Two")] Two = 0x2, [XmlEnum(Name = "Three")] Three = 0x4, [XmlEnum(Name = "OddNumbers")] OddNumbers = One |
[Flags]
[Serializable]
public enum Numbers
{
[XmlEnum(Name = "One")]
One = 0x1,
[XmlEnum(Name = "Two")]
Two = 0x2,
[XmlEnum(Name = "Three")]
Three = 0x4,
[XmlEnum(Name = "OddNumbers")]
OddNumbers = One | Three,
[XmlEnum(Name = "EvenNumbers")]
EvenNumbers = Two,
[XmlEnum(Name = "AllNumbers")]
AllNumbers = One | Two | Three
}
假设我创建了一个具有Numbers
属性的对象,并将该属性设置为evernumbers
。今天,属性中只包含Two
,但我想指定evernumbers
,以便将来如果添加Four
,它也将包含在属性中
但是,如果我使用XmlSerializer.serialize
序列化此对象,XML将显示Two
,因为今天这是相同的基础值
如何强制序列化程序将此属性序列化为
evernumbers
?执行类似操作:将Number
属性标记为XmlIgnore
,并创建另一个string
属性类型以返回enum的字符串值
[Serializable]
public class NumberManager
{
[XmlIgnore]
public Numbers Numbers { get; set; }
[XmlAttribute(AttributeName="Numbers")]
public string NumbersString
{
get { return Numbers.ToString(); }
set { Numbers = (Numbers) Enum.Parse(typeof (Numbers), value); }
}
}
然后序列化NumberManager
我希望能有所帮助。这是一个尝试的好主意,但是Numbers.ToString()仍然不知道这两个枚举中的哪一个最初用于设置值。因为两个值的基础整数是相同的,所以我认为这可能是不可能的。然而,我想在放弃之前与社区进行核实。