C# .NET Core 3 Web API:[FromBody]如何绑定抽象类属性

我有API模型请求的类层次结构：

public class Human
{
    public string Name { get; set; }
    public byte Age { get; set; }
    public IEnumerable<HumanData> Data { get;  set; }
}

public abstract class HumanData
{
    public Guid Id { get; set; }
    public string Text { get; set; }
    public virtual string Type => GetType().Name;
}

public class HealthData : HumanData
{
    public byte Weight { get; set; }
    public byte Growth { get; set; }
    public string Pressure { get; set; }
}

public class AddressData : HumanData
{
    public string City { get; set; }
    public string Street { get; set; }
    public uint House { get; set; }
    public uint Apartment { get; set; }
}

---

但是请求模型没有拉入

humanRequest

变量。原因在

Data

字段

HumanData

类层次结构中。如何制作这样的绑定？

如果您像这样更改动作签名，那么获得模型的唯一方法是

[HttpPost]
    public async Task<IActionResult> Add([FromBody] JObject humanRequest)
    {

        //Functionality
    }
but you will have untyped Object in this case and you have to read it like this:
var name=humanRequest["Name"].ToString();

{
Id: "0f8fad5b-d9cb-469f-a165-70867728950e"
"Name":"Alex",
"Age":30,
AddressId="0f8fad5b-d9cb-469f-a165-70867728950e",
HealthId="0f8fad5b-d9cb-469f-a165-70867728950d",
"Address":{
    "Id": "0f8fad5b-d9cb-469f-a165-70867728950e",
    "Text":"Residence address",
    "City":"Elblag",
    "Street":"1 maja",
    "House":"95",
    "Type":"AddressData"
},
"Health":{
    "Id": "0f8fad5b-d9cb-469f-a165-70867728950d",
    "Text":"Residence address",
    "Weight":"75",
    "Growth":"179",
    "Pressure":"120/85",
    "Type":"HealthData"
}
}

您的Json模型应该如下所示

[HttpPost]
    public async Task<IActionResult> Add([FromBody] JObject humanRequest)
    {

        //Functionality
    }
but you will have untyped Object in this case and you have to read it like this:
var name=humanRequest["Name"].ToString();

{
Id: "0f8fad5b-d9cb-469f-a165-70867728950e"
"Name":"Alex",
"Age":30,
AddressId="0f8fad5b-d9cb-469f-a165-70867728950e",
HealthId="0f8fad5b-d9cb-469f-a165-70867728950d",
"Address":{
    "Id": "0f8fad5b-d9cb-469f-a165-70867728950e",
    "Text":"Residence address",
    "City":"Elblag",
    "Street":"1 maja",
    "House":"95",
    "Type":"AddressData"
},
"Health":{
    "Id": "0f8fad5b-d9cb-469f-a165-70867728950d",
    "Text":"Residence address",
    "Weight":"75",
    "Growth":"179",
    "Pressure":"120/85",
    "Type":"HealthData"
}
}

---

但老实说，我不明白你为什么需要3张桌子放人。在大多数情况下，您将拥有一对一的关系。我想在1中合并所有这3个表。

您使用的是哪个JSON序列化器？我使用的是NeNoToStutJSON。

{
Id: "0f8fad5b-d9cb-469f-a165-70867728950e"
"Name":"Alex",
"Age":30,
AddressId="0f8fad5b-d9cb-469f-a165-70867728950e",
HealthId="0f8fad5b-d9cb-469f-a165-70867728950d",
"Address":{
    "Id": "0f8fad5b-d9cb-469f-a165-70867728950e",
    "Text":"Residence address",
    "City":"Elblag",
    "Street":"1 maja",
    "House":"95",
    "Type":"AddressData"
},
"Health":{
    "Id": "0f8fad5b-d9cb-469f-a165-70867728950d",
    "Text":"Residence address",
    "Weight":"75",
    "Growth":"179",
    "Pressure":"120/85",
    "Type":"HealthData"
}
}