C# 动态加载DLL
我有以下主要方法。LocalCabelTV和LocalDishTV类位于主应用程序中。程序运行良好 我想将LocalCabelTV和LocalDishTV保存在单独的dll文件中。我想知道如何在运行时加载这些类?我知道我们不会使用switch,而是for循环来查找在特定目录中实现IVideSource接口的所有dll文件,并加载这些文件 需要知道如何动态加载DLL、创建对象和使用它们的方法吗?C# 动态加载DLL,c#,.net,C#,.net,我有以下主要方法。LocalCabelTV和LocalDishTV类位于主应用程序中。程序运行良好 我想将LocalCabelTV和LocalDishTV保存在单独的dll文件中。我想知道如何在运行时加载这些类?我知道我们不会使用switch,而是for循环来查找在特定目录中实现IVideSource接口的所有dll文件,并加载这些文件 需要知道如何动态加载DLL、创建对象和使用它们的方法吗? foreach (string dll in Directory.GetFiles("C:\DLLs\
foreach (string dll in Directory.GetFiles("C:\DLLs\*.dll"))
{
Assembly assemb = Assembly.LoadFrom(dll);
??
}
以下操作很好:
static void Main(string[] args)
{
SmartTv myTv = new SmartTv();
Console.WriteLine("Select A source to get TV Guide and Play");
Console.WriteLine("1. Local Cable TV\n2. Local Dish TV");
ConsoleKeyInfo input = Console.ReadKey();
switch (input.KeyChar)
{
case '1':
myTv.VideoSource = new LocalCabelTv();
break;
case '2':
myTv.VideoSource = new LocalDishTv();
break;
}
Console.WriteLine();
myTv.ShowTvGuide();
myTv.PlayTV();
Console.ReadKey();
}
class SmartTv
{
IVideoSource currentVideoSource = null;
public IVideoSource VideoSource
{
get
{
return currentVideoSource;
}
set
{
currentVideoSource = value;
}
}
public void ShowTvGuide()
{
if (currentVideoSource != null)
{
Console.WriteLine(currentVideoSource.GetTvGuide());
}
else
{
Console.WriteLine("Please select a Video Source to get TV guide from");
}
}
public void PlayTV()
{
if (currentVideoSource != null)
{
Console.WriteLine(currentVideoSource.PlayVideo());
}
else
{
Console.WriteLine("Please select a Video Source to play");
}
}
class LocalCabelTv : IVideoSource
{
const string SOURCE_NAME = "Local Cabel TV";
string IVideoSource.GetTvGuide()
{
return string.Format("Getting TV guide from - {0}", SOURCE_NAME);
}
string IVideoSource.PlayVideo()
{
return string.Format("Playing - {0}", SOURCE_NAME);
}
}
class LocalDishTv : IVideoSource
{
const string SOURCE_NAME = "Local DISH TV";
string IVideoSource.GetTvGuide()
{
return string.Format("Getting TV guide from - {0}", SOURCE_NAME);
}
string IVideoSource.PlayVideo()
{
return string.Format("Playing - {0}", SOURCE_NAME);
}
}
class SmartTv
{
IVideoSource currentVideoSource = null;
public IVideoSource VideoSource
{
get
{
return currentVideoSource;
}
set
{
currentVideoSource = value;
}
}
public void ShowTvGuide()
{
if (currentVideoSource != null)
{
Console.WriteLine(currentVideoSource.GetTvGuide());
}
else
{
Console.WriteLine("Please select a Video Source to get TV guide from");
}
}
public void PlayTV()
{
if (currentVideoSource != null)
{
Console.WriteLine(currentVideoSource.PlayVideo());
}
else
{
Console.WriteLine("Please select a Video Source to play");
}
}
class LocalCabelTv : IVideoSource
{
const string SOURCE_NAME = "Local Cabel TV";
string IVideoSource.GetTvGuide()
{
return string.Format("Getting TV guide from - {0}", SOURCE_NAME);
}
string IVideoSource.PlayVideo()
{
return string.Format("Playing - {0}", SOURCE_NAME);
}
}
class LocalDishTv : IVideoSource
{
const string SOURCE_NAME = "Local DISH TV";
string IVideoSource.GetTvGuide()
{
return string.Format("Getting TV guide from - {0}", SOURCE_NAME);
}
string IVideoSource.PlayVideo()
{
return string.Format("Playing - {0}", SOURCE_NAME);
}
}
class SmartTv
{
IVideoSource currentVideoSource = null;
public IVideoSource VideoSource
{
get
{
return currentVideoSource;
}
set
{
currentVideoSource = value;
}
}
public void ShowTvGuide()
{
if (currentVideoSource != null)
{
Console.WriteLine(currentVideoSource.GetTvGuide());
}
else
{
Console.WriteLine("Please select a Video Source to get TV guide from");
}
}
public void PlayTV()
{
if (currentVideoSource != null)
{
Console.WriteLine(currentVideoSource.PlayVideo());
}
else
{
Console.WriteLine("Please select a Video Source to play");
}
}
class LocalCabelTv : IVideoSource
{
const string SOURCE_NAME = "Local Cabel TV";
string IVideoSource.GetTvGuide()
{
return string.Format("Getting TV guide from - {0}", SOURCE_NAME);
}
string IVideoSource.PlayVideo()
{
return string.Format("Playing - {0}", SOURCE_NAME);
}
}
class LocalDishTv : IVideoSource
{
const string SOURCE_NAME = "Local DISH TV";
string IVideoSource.GetTvGuide()
{
return string.Format("Getting TV guide from - {0}", SOURCE_NAME);
}
string IVideoSource.PlayVideo()
{
return string.Format("Playing - {0}", SOURCE_NAME);
}
}
要在运行时加载此程序集并创建对象,请执行以下操作:
Assembly MyDALL = Assembly.Load("DALL"); // DALL is name of my dll
Type MyLoadClass = MyDALL.GetType("DALL.LoadClass"); // LoadClass is my class
object obj = Activator.CreateInstance(Type.GetType("DALL.LoadClass, DALL", true));
对于动态方法,也可以使用动态方法。其速度比反射快(此方法仅需Activator所需时间的十分之一)
下面是使用动态方法创建对象的示例代码
void CreateMethod(ConstructorInfo target)
{
DynamicMethod dynamic = new DynamicMethod(string.Empty,
typeof(object),
new Type[0],
target.DeclaringType);
methodHandler = (MethodInvoker)dynamic.CreateDelegate(typeof(MethodInvoker));
}
有关更多信息,请查看以下链接:
编辑:正如user@taffer提到的,DynamicMethod.CreateDelegate比反射慢得多。因此,只有在创建的委托被调用数百次或数千次时,我才会使用它。使用带缓存的Activator更快。其次,Activator对于无参数构造函数的速度非常快,除非你实例化了太多类型,这使得内部的小缓存变得无用。你需要用所需的类加载DLL并迭代它们的类型,而不是寻找那些实现了
ivideource
的类并激活它们:
public static IEnumerable<IVideoSource> GetVideoSources(List<string> assemblyPathes)
{
IEnumerable<Assembly> yourAssembliesWithClasses = assemblyPathes.Select(x => Assembly.Load(x));
IEnumerable<Type> implementingTypes = yourAssembliesWithClasses
.GetTypes()
.Where(x => x.IsAssignableFrom(IVideoSource));
return implementingTypes.Select(x => Activator.CreateInstance(x));
}
公共静态IEnumerable GetVideoSources(列表汇编路径)
{
IEnumerable yourAssembliesWithClasses=AssemblyPaths.Select(x=>Assembly.Load(x));
IEnumerable implementingTypes=YourAssembliesWithClass
.GetTypes()
其中(x=>x.IsAssignableFrom(IVideoSource));
返回implementingTypes.Select(x=>Activator.CreateInstance(x));
}
请注意,
Activator.CreateInstance()
要求类型具有空构造函数,如果它们没有可以使用的构造函数,Type.GetUniGetUninitializedObject(Type)
从FormatterServices
初始化它们。您不想使用反射生成代码。发出除非您确实必须。。。想想那个可怜的程序员,他将取代你,不得不学习这些代码……同一个用户总是可以选择碟形或有线电视吗?如果是这样的话,为什么不把这两者都作为项目的参考呢?不需要动态检测。您可能想了解MEF()