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C# 如何在xml中逐个选取逗号分隔的属性值作为c中的循环#_C#_Xml_Entity Attribute Value - Fatal编程技术网

C# 如何在xml中逐个选取逗号分隔的属性值作为c中的循环#

C# 如何在xml中逐个选取逗号分隔的属性值作为c中的循环#,c#,xml,entity-attribute-value,C#,Xml,Entity Attribute Value,我想在循环中使用xml中的TestCondition下定义的逗号分隔属性值,以便进一步执行我的代码。请查找示例xml,如下所示: <DrWatson> <Bugs Name="Testing New things" TestCondition="STATE,STATUS"> <Bug> <family>ESG</family> <product>Dr.Watson</prod

我想在循环中使用xml中的
TestCondition
下定义的逗号分隔属性值,以便进一步执行我的代码。请查找示例xml,如下所示:

    <DrWatson>
  <Bugs Name="Testing New things" TestCondition="STATE,STATUS">
    <Bug>
      <family>ESG</family>
      <product>Dr.Watson</product>
      <version>Xpress API</version>
      <productarea>1</productarea>
      <subarea>Blank</subarea>
      <title>Bug.AddNote#1 : Dr.Watson Framework by Aman</title>
      <description>test</description>
      <appLanguages>English~~Bug</appLanguages>
      <platforms>Win XP All~~English~~Bug</platforms>
      <state>Open</state>
      <status>NeedsReview</status>
      <reason>Blank</reason>
      <failureType>Unspecified</failureType>
      <Frequency>Unknown</Frequency>
      <severity>0</severity>
      <priority>0</priority>
      <methodFound>Blank</methodFound>
      <foundInBuild>1</foundInBuild>
      <dev>bansal</dev>
      <qe>sdawar</qe>
      <keyword>Blank</keyword>
      <duplicateId>Blank</duplicateId>
      <note></note>
    </Bug>
    <Bug>
      <family>ESG</family>
      <product>Dr.Watson</product>
      <version>Xpress API</version>
      <productarea>1</productarea>
      <subarea>Blank</subarea>
      <title>Bug.AddNote#1 : Dr.Watson Framework by Aman</title>
      <description>test</description>
      <appLanguages>English~~Bug</appLanguages>
      <platforms>Win XP All~~English~~Bug</platforms>
      <state>Open</state>
      <status>ToFix</status>
      <reason>Blank</reason>
      <failureType>Unspecified</failureType>
      <Frequency>Unknown</Frequency>
      <severity>0</severity>
      <priority>0</priority>
      <methodFound>Blank</methodFound>
      <foundInBuild>1</foundInBuild>
      <dev>bansal</dev>
      <qe>sdawar</qe>
      <keyword>Blank</keyword>
      <duplicateId>Blank</duplicateId>
      <note></note>
    </Bug>
  </Bugs>
  <Bugs Name="STATUS" TestCondition="STATUS">
    <Bug>
      <family>ESG</family>
      <product>Dr.Watson</product>
      <version>Xpress API</version>
      <productarea>1</productarea>
      <subarea>Blank</subarea>
      <title>Bug.AddNote#1 : Dr.Watson Framework by Aman</title>
      <description>test</description>
      <appLanguages>English~~Bug</appLanguages>
      <platforms>Win XP All~~English~~Bug</platforms>
      <state>Open</state>
      <status>NeedsReview</status>
      <reason>Blank</reason>
      <failureType>Unspecified</failureType>
      <Frequency>Unknown</Frequency>
      <severity>0</severity>
      <priority>0</priority>
      <methodFound>Blank</methodFound>
      <foundInBuild>1</foundInBuild>
      <dev>bansal</dev>
      <qe>sdawar</qe>
      <keyword>Blank</keyword>
      <duplicateId>Blank</duplicateId>
      <note></note>
    </Bug>
    <Bug>
      <family>ESG</family>
      <product>Dr.Watson</product>
      <version>Xpress API</version>
      <productarea>1</productarea>
      <subarea>Blank</subarea>
      <title>Bug.AddNote#1 : Dr.Watson Framework by Aman</title>
      <description>test</description>
      <appLanguages>English~~Bug</appLanguages>
      <platforms>Win XP All~~English~~Bug</platforms>
      <state>Open</state>
      <status>ToFix</status>
      <reason>Blank</reason>
      <failureType>Unspecified</failureType>
      <Frequency>Unknown</Frequency>
      <severity>0</severity>
      <priority>0</priority>
      <methodFound>Blank</methodFound>
      <foundInBuild>1</foundInBuild>
      <dev>bansal</dev>
      <qe>sdawar</qe>
      <keyword>Blank</keyword>
      <duplicateId>Blank</duplicateId>
      <note></note>
    </Bug>
  </Bugs>
</DrWatson>
attrVal_New = Update_Bugs[m].Attributes["TestCondition"].Value;
string attributelowercase = attrVal_New.ToLower();

m++;

我想要的是在
TestCondition
下逐个使用可用的“STATE”和“STATUS”。请建议。

假设您的真实xml是有效的

string[] vals = XDocument.Load(fName)
                    .Root
                    .Element("Bugs")
                    .Attribute("TestCondition")
                    .Value.Split(',');

您可以使用foreach循环和string.Split方法,如下所示:

XElement bugsElement = XDocument.Load(fName)
                .Root
                .Element("DrWatson");
List<string> vals = new List<string>();
foreach (XElement el in bugsElement)
{
    vals.AddRange(bugsElement.Attribute("TestCondition").Value.Split(','));
}
返回

new string[] {"STATE","STATUS","HELP","WHATEVER"};

你试过谷歌搜索吗?“XML属性”部分与您的问题完全无关,特别是因为您已经解决了它。实际上,在TestCondition下,XML中还有其他属性可用,我希望一次读取所有属性,以便在代码中使用for循环进一步迭代它们。
new string[] {"STATE","STATUS","HELP","WHATEVER"};