C# xaml DataGrid绑定到dictionary中dictionary中的dictionary

我想将xaml DataGrid绑定到包含以下内容的模型：

TheModel{
  instanceOfClassA
}

ClassA{
  someProps
  Dictionary<string, classB>
}

ClassB{
  someOtherProps
  Dictionary<string, classC>
}

ClassC{
  someMoreProps
}

TheModel{
实例FClassa
}
甲级{
一些道具
字典
}
B类{
其他道具
字典
}
C类{
更多道具
}

这意味着在DataGrid中，ClassA中ClassB中的每个ClassC都有一行，列包含所有三个字典的数据

我不想在模型内部实现TOList方法，因为这会打破模型和视图之间的分离

我可以使用xaml元素吗

谢谢

---

Philipp.

我认为您需要在DataGrid中将数据表示为分层行。你可以这样做

<DataGrid AutoGenerateColumns="False"
          ItemsSource="{Binding Data}"
          RowDetailsVisibilityMode="Visible">

  <DataGrid.Columns>
    <DataGridTextColumn Binding="{Binding P1}" />
    <DataGridTextColumn Binding="{Binding P2}" />
  </DataGrid.Columns>

  <DataGrid.RowDetailsTemplate>

    <DataTemplate>

      <DataGrid AutoGenerateColumns="False"
                ItemsSource="{Binding DictionaryInA.Values}"
                RowDetailsVisibilityMode="Visible">

        <DataGrid.RowDetailsTemplate>

          <DataTemplate>

            <DataGrid AutoGenerateColumns="False"
                      ItemsSource="{Binding DictionaryInB.Values}">

              <DataGrid.Columns>
                <DataGridTextColumn Binding="{Binding P1}" />
                <DataGridTextColumn Binding="{Binding P2}" />
              </DataGrid.Columns>

            </DataGrid>

          </DataTemplate>

        </DataGrid.RowDetailsTemplate>

        <DataGrid.Columns>
          <DataGridTextColumn Binding="{Binding P1}" />
          <DataGridTextColumn Binding="{Binding P2}" />
        </DataGrid.Columns>

      </DataGrid>
    </DataTemplate>
  </DataGrid.RowDetailsTemplate>
</DataGrid>

- Class A Row 1 - Class B Row 1 - Class C Row 1 - Class C Row 2 - Class C Row N - Class B Row 2 - Class C Row 1 - Class C Row 2 - Class C Row N - Class B Row N Class C Row 1 Class C Row 2 Class C Row N - Class A Row 2 - Class B Row 1 - Class C Row 1 - Class C Row 2 - Class C Row N - Class B Row 2 - Class C Row 1 - Class C Row 2 - Class C Row N - Class B Row N Class C Row 1 Class C Row 2 Class C Row N - Class A Row N - Class B Row 1 - Class C Row 1 - Class C Row 2 - Class C Row N - Class B Row 2 - Class C Row 1 - Class C Row 2 - Class C Row N - Class B Row N Class C Row 1 Class C Row 2 Class C Row N

public IEnumerable FlattenedModel
{
    get
    {
        return (from b in TheModel.InstanceOfClassA.DictionaryInA.Values
                from c in b.DictionaryInB.Values
                select new
                {
                    PropertyA1 = TheModel.PropertyA1,
                    PropertyA2 = TheModel.PropertyA2,
                    PropertyB1 = b.PropertyB1,
                    PropertyB2 = b.PropertyB2,
                    PropertyC1 = c.PropertyC1,
                    PropertyC2 = c.PropertyC2
                }).ToList();
    }
}

如果你不能做包装器，那么转换器也能工作

public class FlattenTheModelConverter : IValueConverter
{
    public object Convert(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
    {
        var InstanceOfTheModel = value as TheModel;

        return (from b in InstanceOfTheModel.InstanceOfClassA.DictionaryInA.Values
                from c in b.DictionaryInB.Values
                select new
                {
                    PropertyA1 = InstanceOfTheModel .PropertyA1,
                    PropertyA2 = InstanceOfTheModel .PropertyA2,
                    PropertyB1 = b.PropertyB1,
                    PropertyB2 = b.PropertyB2,
                    PropertyC1 = c.PropertyC1,
                    PropertyC2 = c.PropertyC2
                }).ToList();
    }

    public object ConvertBack(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
    {
        throw new NotImplementedException();
    }
}

如果您决定使用转换器，则需要按如下方式修改XAML

<DataGrid ItemsSource="{Binding TheModel, Converter={StaticResource FlattenTheModelConverter}, Mode=OneWay}">

Hmm我不想添加或显示行详细信息。。我只想将我的数据层次结构扁平化为一个数据网格。更新了答案，包括如何转换和显示扁平数据的信息。