C# 如何实现将复杂类型序列化/反序列化为简单类型的Newtonsoft JSON转换器
我期待着实施。当前,当我尝试序列化/反序列化枚举时,它将其序列化为一个复杂对象。例如,对象颜色:C# 如何实现将复杂类型序列化/反序列化为简单类型的Newtonsoft JSON转换器,c#,json,serialization,json.net,json-deserialization,C#,Json,Serialization,Json.net,Json Deserialization,我期待着实施。当前,当我尝试序列化/反序列化枚举时,它将其序列化为一个复杂对象。例如,对象颜色: public class Color : Enumeration<Color, int> { public static readonly Color Red = new Color(1, "Red"); public static readonly Color Blue = new Color(2, "Blue"); public static readonly
public class Color : Enumeration<Color, int>
{
public static readonly Color Red = new Color(1, "Red");
public static readonly Color Blue = new Color(2, "Blue");
public static readonly Color Green = new Color(3, "Green");
private Color(int value, string displayName) : base(value, displayName) { }
}
在这样的复杂对象中:
public class OtherClass
{
public Color Color {get; set;}
public string Description {get; set;}
}
{
"Description" : "Other Description",
"Color" :
{
"_value": 2,
"_displayName": "Something"
}
}
{
"Description" : "Other Description",
"Color" : 2
}
class EnumerationConverter<T> : JsonConverter where T : Headspring.Enumeration<T, int>
{
public override bool CanConvert(Type objectType)
{
return objectType == typeof(T);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
int val = Convert.ToInt32(reader.Value);
return Headspring.Enumeration<T, int>.FromValue(val);
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
var enumVal = (Headspring.Enumeration<T, int>)value;
writer.WriteValue(enumVal.Value);
}
}
[JsonConverter(typeof(EnumerationConverter<Color>))]
public class Color : Headspring.Enumeration<Color, int>
{
public static readonly Color Red = new Color(1, "Red");
public static readonly Color Blue = new Color(2, "Blue");
public static readonly Color Green = new Color(3, "Green");
private Color(int value, string displayName) : base(value, displayName) { }
}
它将按如下方式序列化:
public class OtherClass
{
public Color Color {get; set;}
public string Description {get; set;}
}
{
"Description" : "Other Description",
"Color" :
{
"_value": 2,
"_displayName": "Something"
}
}
{
"Description" : "Other Description",
"Color" : 2
}
class EnumerationConverter<T> : JsonConverter where T : Headspring.Enumeration<T, int>
{
public override bool CanConvert(Type objectType)
{
return objectType == typeof(T);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
int val = Convert.ToInt32(reader.Value);
return Headspring.Enumeration<T, int>.FromValue(val);
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
var enumVal = (Headspring.Enumeration<T, int>)value;
writer.WriteValue(enumVal.Value);
}
}
[JsonConverter(typeof(EnumerationConverter<Color>))]
public class Color : Headspring.Enumeration<Color, int>
{
public static readonly Color Red = new Color(1, "Red");
public static readonly Color Blue = new Color(2, "Blue");
public static readonly Color Green = new Color(3, "Green");
private Color(int value, string displayName) : base(value, displayName) { }
}
有没有办法让json convert像这样序列化复杂对象:
public class OtherClass
{
public Color Color {get; set;}
public string Description {get; set;}
}
{
"Description" : "Other Description",
"Color" :
{
"_value": 2,
"_displayName": "Something"
}
}
{
"Description" : "Other Description",
"Color" : 2
}
class EnumerationConverter<T> : JsonConverter where T : Headspring.Enumeration<T, int>
{
public override bool CanConvert(Type objectType)
{
return objectType == typeof(T);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
int val = Convert.ToInt32(reader.Value);
return Headspring.Enumeration<T, int>.FromValue(val);
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
var enumVal = (Headspring.Enumeration<T, int>)value;
writer.WriteValue(enumVal.Value);
}
}
[JsonConverter(typeof(EnumerationConverter<Color>))]
public class Color : Headspring.Enumeration<Color, int>
{
public static readonly Color Red = new Color(1, "Red");
public static readonly Color Blue = new Color(2, "Blue");
public static readonly Color Green = new Color(3, "Green");
private Color(int value, string displayName) : base(value, displayName) { }
}
我可以使用枚举类中的FromValue方法,仅从值创建正确的颜色对象。我似乎无法让json转换将属性值作为Color对象的“值”
为了实现这一点,我可以用什么方式编写WriteJson并创建转换器的方法
public class EnumerationConverter : JsonCreationConverter<IEnumeration>
{
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
}
protected override IEnumeration Create(Type objectType, JObject jObject)
{
}
}
公共类枚举转换器:JsonCreationConverter
{
公共重写void WriteJson(JsonWriter编写器、对象值、JsonSerializer序列化器)
{
}
受保护的重写IEnumeration创建(类型objectType,JObject JObject)
{
}
}
您可以为您的源泉.枚举
-派生类创建一个通用转换器,如下所示:
public class OtherClass
{
public Color Color {get; set;}
public string Description {get; set;}
}
{
"Description" : "Other Description",
"Color" :
{
"_value": 2,
"_displayName": "Something"
}
}
{
"Description" : "Other Description",
"Color" : 2
}
class EnumerationConverter<T> : JsonConverter where T : Headspring.Enumeration<T, int>
{
public override bool CanConvert(Type objectType)
{
return objectType == typeof(T);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
int val = Convert.ToInt32(reader.Value);
return Headspring.Enumeration<T, int>.FromValue(val);
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
var enumVal = (Headspring.Enumeration<T, int>)value;
writer.WriteValue(enumVal.Value);
}
}
[JsonConverter(typeof(EnumerationConverter<Color>))]
public class Color : Headspring.Enumeration<Color, int>
{
public static readonly Color Red = new Color(1, "Red");
public static readonly Color Blue = new Color(2, "Blue");
public static readonly Color Green = new Color(3, "Green");
private Color(int value, string displayName) : base(value, displayName) { }
}
下面是一个往返演示: