C# 进程\u OutputDataReceived没有重载与委托System.Diagnostics.DataReceivedEventHandler匹配

这个错误以前从未发生过。这是我的密码

        private Process process = null;
    private void button5_Click(object sender, EventArgs e)
    {
        if (null != process)
        {
            process.Dispose();
        }

        process = new Process();
        process.StartInfo.FileName = "world.exe";
        process.StartInfo.Arguments = "";
        process.StartInfo.UseShellExecute = false;
        process.EnableRaisingEvents = true;
        process.StartInfo.CreateNoWindow = true;
        process.StartInfo.RedirectStandardOutput = true;

        process.OutputDataReceived += new DataReceivedEventHandler(process_OutputDataReceived);
        process.Exited += new EventHandler(process_Exited);
        process.Start();
        process.BeginOutputReadLine();
    }

    private void process_OutputDataReceived(object sender, DataReceivedEventArgs e)
    {
    }

以下是我得到的一个错误：

            process.OutputDataReceived += new DataReceivedEventHandler(process_OutputDataReceived);

在我写下之前，上面的内容是好的

    private void process_OutputDataReceived(object sender, DataReceivedEventArgs e)
    {
    }

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我们将不胜感激。我不知道这怎么会比现在更具体

我能想到的唯一一件事是您有一个名称空间冲突（即，您的环境中有其他与所使用的类的名称相匹配的类）

尝试使用显式命名空间声明：

    process.OutputDataReceived += new System.Diagnostics.DataReceivedEventHandler(process_OutputDataReceived);

    private void process_OutputDataReceived(object sender, System.Diagnostics.DataReceivedEventArgs e)
    {
    }

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