C# WriteableBitmapEx.DrawRectangle厚度?
如何更改使用WriteableBitmapEx.DrawRectangle扩展方法绘制的矩形轮廓的厚度/重量?我用于绘制矩形的代码是:C# WriteableBitmapEx.DrawRectangle厚度?,c#,windows-phone-7,writeablebitmap,drawrectangle,writeablebitmapex,C#,Windows Phone 7,Writeablebitmap,Drawrectangle,Writeablebitmapex,如何更改使用WriteableBitmapEx.DrawRectangle扩展方法绘制的矩形轮廓的厚度/重量?我用于绘制矩形的代码是: WriteableBitmap wbmp = new WriteableBitmap(bmp); wbmp.DrawRectangle(0, 0, 480, 360, Colors.DarkGray); 使用此代码,以1px绘制的矩形的厚度。从 这里有一个很好的解决方法,使用了“矩形”中不太为人所知的“充气”方法: int pen_thickness = 5;
WriteableBitmap wbmp = new WriteableBitmap(bmp);
wbmp.DrawRectangle(0, 0, 480, 360, Colors.DarkGray);
使用此代码,以1px绘制的矩形的厚度。从
这里有一个很好的解决方法,使用了“矩形”中不太为人所知的“充气”方法:
int pen_thickness = 5;
Rectangle original_rect = new Rect(0, 0, 480, 360); // using the poster's original values
for(int i = 0; i < pen_thickness; i++)
{
Rectangle bigger_rect = Rectangle.Inflate(original_rect, i, i);
wbmp.DrawRectangle(Pens.DarkGray, bigger_rect);
}
int pen_厚度=5;
矩形原始矩形=新矩形(0,0,480,360);//使用海报的原始值
对于(int i=0;i
这将创建一个从最初搜索的矩形展开的矩形。还可以进行快速修改,使厚度一半向内扩展(充气时为负值),一半向外扩展(充气时为正值)。创建了以下内容。。。非常适合于WriteableBitmapEx
private static void DrawRectangle(WriteableBitmap bitmap,
int left, int top, int width, int height, Color color, int thinkness)
{
var x1 = left;
var y1 = top;
var x2 = left + width;
var y2 = top + height;
bitmap.DrawRectangle(x1, y1, x2, y2, color);
for (var i = 0; i < thinkness; i++)
{
bitmap.DrawRectangle(x1--, y1--, x2++, y2++, color);
}
}
private static void DrawRectangle(可写位图),
整数左、整数顶、整数宽度、整数高度、颜色、整数厚度)
{
var x1=左;
变量y1=顶部;
var x2=左侧+宽度;
var y2=顶部+高度;
位图.绘制矩形(x1,y1,x2,y2,颜色);
for(var i=0;i
private static void DrawRectangle(WriteableBitmap bitmap,
int left, int top, int width, int height, Color color, int thinkness)
{
var x1 = left;
var y1 = top;
var x2 = left + width;
var y2 = top + height;
bitmap.DrawRectangle(x1, y1, x2, y2, color);
for (var i = 0; i < thinkness; i++)
{
bitmap.DrawRectangle(x1--, y1--, x2++, y2++, color);
}
}