C# 不经过下一步就可以安装应用程序吗？

这个问题不言自明，但。。 我想创建一个程序，当我执行它时，它将下载一些文件，然后安装它们，例如chrome。但是我如何才能通过下一阶段的安装呢？我使用的是C语言或Java语言。我现在有一些代码可以下载这个文件，但是没有：S

我希望它最终做什么： 1） 下载-安装Chrome 2） 输入gmail acc（proly java scrip？） 3） 其余的可能是类似的

        private void Download()
    {
        WebClient webClient = new WebClient();
        webClient.Headers.Add("user-agent", "Mozilla/5.0 (Windows; Windows NT 5.1; rv:1.9.2.4) Gecko/20100611 Firefox/3.6.4");
        webClient.DownloadFileCompleted += new AsyncCompletedEventHandler(Completed);
        webClient.DownloadProgressChanged += new DownloadProgressChangedEventHandler(ProgressChanged);
        webClient.DownloadFileAsync(new Uri("http://dl.google.com/update2/installers/ChromeSetup.exe"), Environment.GetFolderPath(Environment.SpecialFolder.Desktop));
    }

我不知道下载页面是否会因为客户端标题或其他内容而阻止我。。

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谢谢大家

使用pinvoke，您可以通过SendKey函数向设置窗口处理程序发送快捷方式

[DllImport("User32.Dll", EntryPoint = "PostMessageA")]
    static extern bool PostMessage(
        IntPtr hWnd, 
        uint msg, 
        int wParam, 
        int lParam
        );

    const uint WM_KEYDOWN = 0x100;

    const int WM_a = 0x41;
    const int WM_b = 0x42;
    const int WM_c = 0x43;


    static void Main(string[] args)
    {
        //using Process.GetProcessesByName to get the handle we want  
        Process[] p = Process.GetProcessesByName("notepad");  
        IntPtr pHandle = p[0].MainWindowHandle;  

        //will write "abc" in the open Notepad window
        PostMessage(pHandle, WM_KEYDOWN, WM_a, 0);
        PostMessage(pHandle, WM_KEYDOWN, WM_b, 0);
        PostMessage(pHandle, WM_KEYDOWN, WM_c, 0);
    }

下面是来自的示例代码。它使用函数

[DllImport("User32.Dll", EntryPoint = "PostMessageA")]
    static extern bool PostMessage(
        IntPtr hWnd, 
        uint msg, 
        int wParam, 
        int lParam
        );

    const uint WM_KEYDOWN = 0x100;

    const int WM_a = 0x41;
    const int WM_b = 0x42;
    const int WM_c = 0x43;


    static void Main(string[] args)
    {
        //using Process.GetProcessesByName to get the handle we want  
        Process[] p = Process.GetProcessesByName("notepad");  
        IntPtr pHandle = p[0].MainWindowHandle;  

        //will write "abc" in the open Notepad window
        PostMessage(pHandle, WM_KEYDOWN, WM_a, 0);
        PostMessage(pHandle, WM_KEYDOWN, WM_b, 0);
        PostMessage(pHandle, WM_KEYDOWN, WM_c, 0);
    }