C# Can'；t从.net中的JSON响应中删除.d封装

即使在写了这篇很棒的博文之后，我也无法逃避JSON响应中的.d封装。我不知道我是否做错了什么，所以我将复制服务器端和客户端代码

我正在使用Newtonsoft.JSON库序列化JSON

客户端：

<script type="text/javascript">
$(function () {
    $("#bt").click(function () {
        $.ajax({
            type: "POST",
            url: "<%= Page.ResolveUrl("~/MapView.aspx/GetLocations")%>",
            data: "{ type: '<%= Page.RouteData.Values["type"].ToString() %>', id: '<%= Page.RouteData.Values["id"].ToString() %>' }",
            contentType: "application/json; charset=utf-8",
            dataType: "json",
            dataFilter: function(data) {
                var msg;

                if (typeof (JSON) !== 'undefined' && 
                    typeof (JSON.parse) === 'function')
                    msg = JSON.parse(data);
                else
                    msg = eval('(' + data + ')');

                if (msg.hasOwnProperty('d'))
                    return msg.d;
                else
                    return msg;
            },
            success: function (msg) {
                console.log(msg);
            },
        });
    });
});
</script>

服务器端-更新1

    [System.Web.Services.WebMethod]
    public static void GetLocations(int id, string type)
    {
        string data = "";


        if (type == "attraction")
        {
            var attractions = db.Attraction
                                .Where(a => a.AttractionId == id)
                                .Select(p => new { p.AttractionId, p.Name, p.Description, p.Location })
                                .ToList();


            JArray attractionsJSON = new JArray(
                    from a in attractions
                    select new JObject(
                        new JProperty("id", a.AttractionId),
                        new JProperty("name", a.Name),
                        new JProperty("location", a.Location),
                        new JProperty("description", a.Description)
                        ));

            data = attractionsJSON.ToString();
        }
        else if (type == "category")
        {
            var attractions = db.Attraction

                .Select(p => new { p.AttractionId, p.Name, p.Description, p.Location, p.CategoryId })
                .ToList();

            if (id != 0)
            {
                attractions = attractions.Where(a => a.CategoryId == id)
                    .ToList();
            }


            JArray attractionsJSON = new JArray(
                    from a in attractions
                    select new JObject(
                        new JProperty("id", a.AttractionId),
                        new JProperty("name", a.Name),
                        new JProperty("location", a.Location),
                        new JProperty("description", a.Description)
                        ));

            data = attractionsJSON.ToString();

        }


        var js = new System.Web.Script.Serialization.JavaScriptSerializer();

        HttpContext.Current.Response.Clear();
        HttpContext.Current.Response.ContentType = "application/json; charset=utf-8";
        HttpContext.Current.Response.Write(js.Serialize(data));
        HttpContext.Current.Response.Flush();
        HttpContext.Current.Response.End();
    }
}

---

尝试使用不返回的void方法。而是自己编写输出来响应

  [System.Web.Services.WebMethod]
    public static void GetLocations(int id, string type)
    {
     // var attractions = something ;

     var js = new System.Web.Script.Serialization.JavaScriptSerializer();

        HttpContext.Current.Response.Clear();
        HttpContext.Current.Response.ContentType = "application/json; charset=utf-8";
        HttpContext.Current.Response.Write(  js.Serialize(attractions )  );
        HttpContext.Current.Response.Flush();
        HttpContext.Current.Response.End();
   }

在结束时保持这两次通话非常重要：

flush：确保将输出写入流

---

结束：结束流以防止asp.Net将空Json写入流

尝试从ajax调用中删除

数据类型

参数。从中，请参阅“数据类型：不关你的事”@DanielJ.G。不幸的是，即使没有它，我仍然收到。为什么当我点击这篇文章中的第一个链接时会收到“此网站包含恶意软件”的警告？@Mike它一定与一些被谷歌认定为危险的恶意脚本有关。希望，网站的所有者会解决这些问题。我认为这是答案，看起来我们走在一条很好的道路上，但这并不能解决我的问题。实际上，我得到的是无效的JSON。JSON输出可以在这里看到，您如何使用System.Web.Script.Serialization.JavaScriptSerializer创建JSON？是的，我举了您的确切示例，它按预期删除了.d，但JSON无效。只需将吸引力传递给Serialize（），我不认为需要Jobject，Jarray无论何时访问克罗地亚，请告诉我，我欠你一杯啤酒！：）谢谢，将景点直接传递给对象就是解决方案。

  [System.Web.Services.WebMethod]
    public static void GetLocations(int id, string type)
    {
     // var attractions = something ;

     var js = new System.Web.Script.Serialization.JavaScriptSerializer();

        HttpContext.Current.Response.Clear();
        HttpContext.Current.Response.ContentType = "application/json; charset=utf-8";
        HttpContext.Current.Response.Write(  js.Serialize(attractions )  );
        HttpContext.Current.Response.Flush();
        HttpContext.Current.Response.End();
   }