C# 获取ListViewItem子项

是否有方法访问

TextBox

控件并获取其

Text

属性

迈克尔给了我答案：

这是

FindVisualChild

方法：

ListViewItem lvi = lvPayload.ItemContainerGenerator.ContainerFromIndex(0) as ListViewItem;

---

是的，但首先需要给它一个

名称

属性。命名后，您可以执行以下操作：

ListViewItem lvi = lvPayload.ItemContainerGenerator.ContainerFromIndex(0) as ListViewItem;
// Getting the ContentPresenter of lvi
var cp = FindVisualChild<ContentPresenter>(lvi);

// Finding textBlock from the DataTemplate that is set on that ContentPresenter
var dtmpl = cp.ContentTemplate as DataTemplate;
var tb = (TextBox)dtmpl.FindName("myTb", cp);

//获取lvi的ContentPresenter
var cp=FindVisualChild（lvi）；
//从在该ContentPresenter上设置的DataTemplate中查找textBlock
var dt=cp.ContentTemplate作为数据模板；
var tb=（TextBox）dt.FindName（“{name}”，cp）；

谢谢，但FindVisualChild方法是什么？

public static T FindVisualChild<T>(DependencyObject depObj) where T : DependencyObject
{
    if (depObj != null)
    {
        for (int i = 0; i < VisualTreeHelper.GetChildrenCount(depObj); i++)
        {
            DependencyObject child = VisualTreeHelper.GetChild(depObj, i);
            if (child != null && child is T)
            {
                return (T)child;
            }

            T childItem = FindVisualChild<T>(child);
            if (childItem != null) return childItem;
        }
    }
    return null;
}

ListViewItem lvi = lvPayload.ItemContainerGenerator.ContainerFromIndex(0) as ListViewItem;
// Getting the ContentPresenter of lvi
var cp = FindVisualChild<ContentPresenter>(lvi);

// Finding textBlock from the DataTemplate that is set on that ContentPresenter
var dtmpl = cp.ContentTemplate as DataTemplate;
var tb = (TextBox)dtmpl.FindName("myTb", cp);

// Getting the ContentPresenter of lvi
var cp = FindVisualChild<ContentPresenter>(lvi);

// Finding textBlock from the DataTemplate that is set on that ContentPresenter
var dt = cp.ContentTemplate as DataTemplate;
var tb = (TextBox)dt.FindName("{name}", cp);