C# 将C中嵌套列表中相同索引的项分组#

我想重新排列一个嵌套列表，将列表中相同索引的每个项目分组到一个列表中

这就是我想要实现的目标

输入

输出

{
["a", "m", "x"], 
["b", "n", "y"],
["c", "o", "z"],
}

---

如何使用C#？

实现这一点您要执行的操作称为转置

以下解决方案假设内部的所有阵列长度相同：

var listOfArrays = new List<string[]>(){
    new string[]{"a", "b", "c"}, 
    new string[]{"m", "n", "o"},
    new string[]{"x", "y", "z"},
};
var transposed = new List<string[]>();
var internalSize = listOfArrays[0].Length;
for(int i = 0; i < internalSize; i++)
{
    var column = new List<string>();
    foreach(var array in listOfArrays)
    {
        column.Add(array[i]);
    }
    transposed.Add(column.ToArray());
}

var listOfArrays=new List（）{
新字符串[]{“a”、“b”、“c”}，
新字符串[]{“m”、“n”、“o”}，
新字符串[]{“x”、“y”、“z”}，
};
var transposed=新列表（）；
var internalSize=listOfArrays[0]。长度；
对于（int i=0；i

您可以使用和

GroupBy

：

var x = new[]{new[]{"a", "b", "c"}, new[]{"m", "n", "o"}, new[]{"x", "y", "z"}, };
var arrs = x
    .SelectMany(arr => arr.Select((inner, i) => (inner, i))) // project inner elements with index & flatten
    .GroupBy(i => i.i) // group by element index
    .Select(g => g.Select(gi => gi.inner).ToArray()) // select element from projection
    .ToArray();

---

@JohnathanBarclay谢谢你，修正了。谢谢这项工作。你试图实现什么？这将被称为

var x = new[]{new[]{"a", "b", "c"}, new[]{"m", "n", "o"}, new[]{"x", "y", "z"}, };
var arrs = x
    .SelectMany(arr => arr.Select((inner, i) => (inner, i))) // project inner elements with index & flatten
    .GroupBy(i => i.i) // group by element index
    .Select(g => g.Select(gi => gi.inner).ToArray()) // select element from projection
    .ToArray();