C# 如何从webservice返回JSON

早上好

我需要从我的web服务返回一条消息。下面是我的代码示例，我返回一个字符串

[web method]
public string CheckFeedSubmission()
    {
        string responseText = "";
        try
        {
            //Stuff goes here
            responseText = "It Worked!"
        }
        catch (Exception ex) { responseText = "Opps wehave an error! Exception message:" + ex.Message; }
        return responseText ;
    }

我目前得到以下回应

<string xmlns="http://tempuri.org/"/>

我相信，一旦我有了这个想法，如果需要的话，我将能够归还其他物品。这就是我需要解决的问题

非常感谢所有帮助，提前感谢：）

更新：刚找到这个

 return "{Message:'hello world'}"

我需要像这样的东西吗

 responseText = "{"success" : true, "message" : \"There has been an error. Message: " + ex.Message + "\"}"

使用：

[WebMethod]
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]//Specify return format.
public string CheckFeedSubmission()
    {
        string responseText = "";
        try
        {
            //Stuff goes here
            responseText = "It Worked!"
        }
        catch (Exception ex) { responseText = "Opps wehave an error! Exception message:" + ex.Message; }
        return responseText ;
    }

<string xmlns="http://tempuri.org/"/>
 {"success" : true, "message" : "***Message Here***"}
</string>

返回的结果如下：

[WebMethod]
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]//Specify return format.
public string CheckFeedSubmission()
    {
        string responseText = "";
        try
        {
            //Stuff goes here
            responseText = "It Worked!"
        }
        catch (Exception ex) { responseText = "Opps wehave an error! Exception message:" + ex.Message; }
        return responseText ;
    }

<string xmlns="http://tempuri.org/"/>
 {"success" : true, "message" : "***Message Here***"}
</string>

{“success”：true，“message”：“***message Here***”}

请使用webmethod的属性

   [WebMethod]
    [ScriptMethod(ResponseFormat = ResponseFormat.Json)]

调用者将contenttype设置为application/json以使用webmethod，请尝试以下方法：

   [WebMethod]
    [ScriptMethod(ResponseFormat = ResponseFormat.Json)]

[WebMethod] 
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]//Specify return format. 
public bool addUser(UserModel um)
    {
        bool result = false;
        result = Conversion.intToBool(SplashAwardsDB.executeNonQuery(
            "INSERT INTO dbo.User ("
            + "userName, password, firstName, lastName, address, contactNo, birthDate, familyID, familyRole, x, y ) "
            + " VALUES ("
            + "'" + um.userName + "', "
            + "'" + um.password + "', "
            + "'" + um.firstName + "', "
            + "'" + um.lastName + "', "
            + "'" + um.address + "', "
            + "'" + um.contactNo + "', "
            + "'" + um.birthDate + "', "
            + "'" + um.familyID + "', "
            + "'" + um.familyRole + "', "
            + "'" + um.x + "', "
            + "'" + um.y + "')"
            ));
        return result;
    }

---

要删除服务响应中的XML标记，请参阅StackOverflow上的以下回答：

---

这是我针对framewok 4.5.2的解决方案， 在类FilterConfig中添加以下代码， 注意：您将需要lib Newtonsoft

 public class FilterConfig
{
    public static void RegisterGlobalFilters(GlobalFilterCollection filters)
    {
        GlobalConfiguration.Configuration.Formatters.JsonFormatter.SerializerSettings.ReferenceLoopHandling = Newtonsoft.Json.ReferenceLoopHandling.Serialize;
        GlobalConfiguration.Configuration.Formatters.Remove(GlobalConfiguration.Configuration.Formatters.XmlFormatter);
        GlobalConfiguration.Configuration.EnableCors();
        filters.Add(new HandleErrorAttribute());
    }
}

---

不起作用，仍然只返回一个字符串-谢谢，但如上所述，我仍然返回XML字符串实际上它在XML中返回Json。您需要在通话中指定要返回的内容。为什么它以这种格式返回？重新看一看答案。是的，你可以，看一看，我明白了，只是在我的应用程序中测试过，而不是在我的实际web服务及其返回的json中测试过。只需要格式化它，这样我就有了我想要返回的内容：）如果我像我在responseText中那样添加bool来传递真/假，我会正确假设吗？可能是