C# 获取以下字符串中的表名的最有效方法

在这种情况下，获取schema+表名的最有效方法是什么：

选择[t0].[Id]，[t0].[CODE]作为[arg0]，[t0].[DESC]作为[arg1] 从[SchemaName].[TableName]AS[t0] 其中[t0].[Id]@p0

结果需要是：SchemaName.TableName

我用的是C

---

谢谢

我猜，只是一些使用子字符串的好的旧字符串解析。一些代码：

 string q = @"SELECT [t0].[Id], [t0].[CODE] AS [arg0], [t0].[DESC] AS [arg1] FROM [SchemaName].[TableName] AS [t0] WHERE ([t0].[Id] <> @p0)";
            int fromIndex = q.IndexOf("FROM")+5;
            int asIndex = q.IndexOf("AS",fromIndex);
            q = q.Substring(fromIndex, asIndex - fromIndex);

---

或者可以使用正则表达式：

string data = "SELECT [t0].[Id], [t0].[CODE] AS [arg0], [t0].[DESC] AS [arg1] FROM [SchemaName].[TableName] AS [t0] WHERE ([t0].[Id] <> @p0)";
Regex re = new Regex(@"FROM ((\[\w+\]\.?){2}) AS");
Match m = re.Match(data);
if (m.Success){ Console.WriteLine(m.Groups[1]); }

或者，如果您不想包含括号：

string data = "SELECT [t0].[Id], [t0].[CODE] AS [arg0], [t0].[DESC] AS [arg1] FROM [SchemaName].[TableName] AS [t0] WHERE ([t0].[Id] <> @p0)";
Regex re = new Regex(@"FROM \[(\w+)\]\.\[(\w+)\]\ AS");
Match m = re.Match(data);
if (m.Success){ Console.WriteLine("{0}.{1}", m.Groups[1], m.Groups[2]); }

---

此外，您还可以扩展正则表达式以包含联接并处理多个空格