C# 如何从Razor变量指定数组到Dygraph
我在会话[“PnlDataForChart”]中有一个字符串[]包含适当格式的字符串 但我不能在动态图中显示它们。我试图检查dataArray,但在VS调试器中看不到它,并且不确定如何在Firebug中执行 动态图的设置是否正确 来自页面来源:C# 如何从Razor变量指定数组到Dygraph,c#,razor,dygraphs,C#,Razor,Dygraphs,我在会话[“PnlDataForChart”]中有一个字符串[]包含适当格式的字符串 但我不能在动态图中显示它们。我试图检查dataArray,但在VS调试器中看不到它,并且不确定如何在Firebug中执行 动态图的设置是否正确 来自页面来源: var-dataArray=[]; dataArray.push(“日期,Pnl”); dataArray.push(“2016/11/01:01,0.0000”); dataArray.push(“2016/11/01 01:02,0.0000”);
var-dataArray=[];
dataArray.push(“日期,Pnl”);
dataArray.push(“2016/11/01:01,0.0000”);
dataArray.push(“2016/11/01 01:02,0.0000”);
dataArray.push(“2016/11/01 01:03,0.0000”);
dataArray.push(“2016/11/01 01:04,0.0000”);
dataArray.push(“2016/11/01 01:05,0.0000”);
dataArray.push(“2016/11/01 01:06,0.0000”);
从查看页面:
var dataArray=[];
@{
foreach(字符串[])会话[“PnlDataForChart”]中的变量行)
{
dataArray.push(“@line”);
}
}
g=新动态图(
document.getElementById(“graphdiv”),
数据阵列
);
您的代码中有很多乱七八糟的地方。只是一些错误:
之后有
,这是不必要的
块中,所以无法放置
。在脚本块中,您只能使用JavaScript语法李>
@:dataArray.push(“@line”)代码>
var dataArray = new string[] {
"Date,Temperature",
"2008-05-07,75",
"2008-05-08,70",
"2008-05-09,80"
};
Session["PnlDataForChart"] = dataArray;
和视图:
<script src="~/Scripts/dygraph.js"></script>
<div id="ExportDiv">
<div id="graphdiv"></div>
</div>
<script type="text/javascript">
var dataArray = [];
@{
foreach (var line in (string[])Session["PnlDataForChart"])
{
@:dataArray.push("@line");
}
}
g = new Dygraph(document.getElementById("graphdiv"), dataArray.join('\n'));
</script>
var dataArray=[];
@{
foreach(字符串[])会话[“PnlDataForChart”]中的变量行)
{
@:dataArray.push(“@line”);
}
}
g=新的动态图(document.getElementById(“graphdiv”)、dataArray.join('\n');
var dataArray = new string[] {
"Date,Temperature",
"2008-05-07,75",
"2008-05-08,70",
"2008-05-09,80"
};
Session["PnlDataForChart"] = dataArray;
<script src="~/Scripts/dygraph.js"></script>
<div id="ExportDiv">
<div id="graphdiv"></div>
</div>
<script type="text/javascript">
var dataArray = [];
@{
foreach (var line in (string[])Session["PnlDataForChart"])
{
@:dataArray.push("@line");
}
}
g = new Dygraph(document.getElementById("graphdiv"), dataArray.join('\n'));
</script>