c#在未知嵌套元素上使用XSD验证XML
是否可以创建XSD来验证(未知)嵌套结构? 我最近将XML数据更改为层次结构c#在未知嵌套元素上使用XSD验证XML,c#,xml,xsd-validation,C#,Xml,Xsd Validation,是否可以创建XSD来验证(未知)嵌套结构? 我最近将XML数据更改为层次结构 <root> <record Object_Number="1" Object_Level="1" Object_Heading="Introduction" Object_Text="" Milestones="" Unique_ID="" Field_type="Info" SG_attribute="" Object_Identifier="1" Object_URL="doors://
<root>
<record Object_Number="1" Object_Level="1" Object_Heading="Introduction" Object_Text="" Milestones="" Unique_ID="" Field_type="Info" SG_attribute="" Object_Identifier="1" Object_URL="doors://D1DDBAPP04:36677/?version=2&prodID=0&view=0000001a&urn=urn:telelogic::1-432aa0956f684cff-O-1-00028f60">
<record Object_Number="1.1" Object_Level="2" Object_Heading="What is " Object_Text="" Milestones="" Unique_ID="" Field_type="Info" SG_attribute="" Object_Identifier="23" Object_URL="doors://D1DDBAPP04:36677/?version=2&prodID=0&view=0000001a&urn=urn:telelogic::1-432aa0956f684cff-O-23-00028f60">
<record Object_Number="1.1.0-1" Object_Level="3" Object_Heading="" Object_Text="This document is, in fact, a database that summarizes specification and different aspects of diagnostic functions implemented in the system." Milestones="" Unique_ID="" Field_type="Info" SG_attribute="" Object_Identifier="24" Object_URL="doors://D1DDBAPP04:36677/?version=2&prodID=0&view=0000001a&urn=urn:telelogic::1-432aa0956f684cff-O-24-00028f60"></record></record>
<record Object_Number="1.2" Object_Level="2" Object_Heading="Review Checklist"
{
msg+=错误消息;
//WriteLine(“{0}”,err.Message);
//错误=正确;
});
如果(msg==“”)
e、 结果=真;
我用VisualStudio生成的XSD模式
现在,对于分层数据,生成的XSD似乎遵循了深层结构,这对于已知级别的深度来说是好的,但是对于另一个深度来说则会失败
<xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="root">
<xs:complexType>
<xs:sequence>
<xs:element maxOccurs="unbounded" name="record">
<xs:complexType>
<xs:sequence minOccurs="0">
<xs:element maxOccurs="unbounded" name="record">
<xs:complexType>
<xs:sequence minOccurs="0">
<xs:element maxOccurs="unbounded" name="record">
<xs:complexType>
<xs:sequence minOccurs="0">
<xs:element maxOccurs="unbounded" name="record">
<xs:complexType>
<xs:attribute name="Object_Number" type="xs:string" use="required" />
<xs:attribute name="Object_Level" type="xs:unsignedByte" use="required" />
<xs:attribute name="Object_Heading" type="xs:string" use="required" />
<xs:attribute name="Object_Text" type="xs:string" use="required" />
<xs:attribute name="Milestones" type="xs:string" use="required" />
<xs:attribute name="Unique_ID" type="xs:string" use="required" />
<xs:attribute name="Field_type" type="xs:string" use="required" />
<xs:attribute name="SG_attribute" type="xs:string" use="required" />
<xs:attribute name="Object_Identifier" type="xs:unsignedShort" use="required" />
<xs:attribute name="Object_URL" type="xs:string" use="required" />
</xs:complexType>
...
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...
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那么是否可以使用XSD检查嵌套方案
非常感谢您的提示,将结构递归定义为
<xs:element name="record">
<xs:complexType>
<xs:sequence minOccurs="0" maxOccurs="unbounded">
<xs:element ref="record"/>
....
....
xsd架构可以是递归的:
<xs:element name="record">
<xs:complexType>
<xs:sequence minOccurs="0" maxOccurs="unbounded">
<xs:element ref="record"/>
....