C# 使用c在wordpress中以HTML形式发布博客文章#

我想在我的wordpress网站上发布一篇博客文章，但在c#应用程序中使用HTML代码创建它。原因是我在wordpress中为特定类型的帖子设置了一个模板（它有链接到URL等的按钮）。我该如何在c#中处理这件事呢。我使用XML-RPC包来创建新的博客文章，但是它只处理基本的事情，比如标题和内容。我的模板博客文章的HTML代码如下所示：

<!-- wp:group -->
<div class="wp-block-group"><div class="wp-block-group__inner-container"><!-- wp:heading {"level":4} -->
<h4>TITLE GOES HERE</h4>
<!-- /wp:heading -->

<!-- wp:spacer {"height":20} -->
<div style="height:20px" aria-hidden="true" class="wp-block-spacer"></div>
<!-- /wp:spacer -->

<!-- wp:button {"backgroundColor":"luminous-vivid-orange"} -->
<div class="wp-block-button"><a class="wp-block-button__link has-background has-luminous-vivid-orange-background-color" href="https://www.wesbitelinkgoeshere.com">READ MORE</a></div>
<!-- /wp:button -->

按下按钮后，它将从表单上的2个文本框中成功发布新的博客文章，但我希望它使用HTML代码并从中创建博客文章，而不是以字符串内容发布

using System;
using System.Windows.Forms;

using CookComputing.XmlRpc;

public struct blogInfo
{
    public string title;
    public string description;
}

public interface IgetCatList
{
    [CookComputing.XmlRpc.XmlRpcMethod("metaWeblog.newPost")]
    string NewPage(int blogId, string strUserName,
        string strPassword, blogInfo content, int publish);
}

namespace WordpressBlogTest
{
    public partial class Form1 : Form
    {

        public Form1()
        {
            InitializeComponent();
        }

        private void btnPost_Click(object sender, EventArgs e)
        {
            blogInfo newBlogPost = default(blogInfo);
            newBlogPost.title = txtTitle.Text;
            newBlogPost.description = txtPost.Text;

            IgetCatList categories = (IgetCatList)XmlRpcProxyGen.Create(typeof(IgetCatList));
            XmlRpcClientProtocol clientProtocol = (XmlRpcClientProtocol)categories;
            clientProtocol.Url = "https://myblog.com/xmlrpc.php";
            string result = null;
            result = "";
            try
            {
                result = categories.NewPage(1, "username", "password", newBlogPost, 1); MessageBox.Show("Posted to Blog successfullly! Post ID : " + result); txtPost.Text = "";
                txtTitle.Text = "";
            }
            catch (Exception ex)
            {
                MessageBox.Show(ex.Message);
            }
        }
    }
}