C# 使用autofac注册多个dbcontext，其中生成器在注册后无法解析类

我有以下场景，依赖项注入发生在下面给出的类定义之外，因此我无法访问类中的builder对象。问题是DbContext被映射到两个类，因为我需要处理两个不同的数据库。为了创建SomeClass，需要实例化MyRepository和MyOtherRepository，但要做到这一点，需要两个不同的DBContext。这就是问题的症结所在，因为Autofac只接受DbContext映射到MyOtherContext的最后一个映射。非常感谢您为解决此问题提供的任何帮助，谢谢！ 如果需要更多信息，请告诉我

public class DependencyResolver : IDependencyResolver
{
   builder.RegisterType<MyContext>().As<DbContext>().InstancePerLifetimeScope();

  builder.RegisterType<MyOtherContext>().As<DbContext>().InstancePerLifetimeScope();

  builder.RegisterType<RepositoryManager.MyRepository>().As<Types.Repository.IMyRepository>().InstancePerDependency();

  builder.RegisterType<RepositoryManager.MyOtherRepository>().As<Types.Repository.IMyOtherRepository>().InstancePerDependency();
}

试试这个。基本上，您正在寻找Autofac的功能。我更喜欢

因此，如果您注册这样的上下文：

var builder = new ContainerBuilder();                
        builder
            .RegisterType<MyContext>()
            .As<DbContext>()
            .WithMetadata("EFContext", "My");
        builder
            .RegisterType<MyRepository>()
            .AsImplementedInterfaces();

        builder
            .RegisterType<MyOtherContext>()
            .As<DbContext>()
            .WithMetadata("EFContext", "Other");
        builder
            .RegisterType<MyOtherRepository>()
            .AsImplementedInterfaces();

public class SomeClass
{
    private readonly IMyRepository _myRepository;
    private readonly IMyOtherRepository _myOtherRepository;

    public SomeClass(IMyRepository myRepository, IMyOtherRepository myOtherRepository)
    {
        _myRepository = myRepository;
        _myOtherRepository = myOtherRepository;
    }

    public string SayHello()
    {
        return $"Hello from {_myRepository.ContextName()}  and {_myOtherRepository.ContextName()}";
    }
}

public interface IMyOtherRepository
{
    string ContextName();
}

public interface IMyRepository
{
    string ContextName();
}

public class MyContext : DbContext
{
    // Code
}

public class MyOtherContext : DbContext
{
    // Code
}

public class MyRepository : IMyRepository
{
    private readonly IEnumerable<Meta<DbContext>> _context;

    public MyRepository(IEnumerable<Meta<DbContext>> context)
    {
        _context = context;
        // Code
    }

    public string ContextName() => _context.First(x => x.Metadata["EFContext"].Equals("My")).Value.GetType().Name;
}

public class MyOtherRepository : IMyOtherRepository
{
    private readonly IEnumerable<Meta<DbContext>> _context;

    public MyOtherRepository(IEnumerable<Meta<DbContext>> context)
    {
        this._context = context;
        // Code
    }

    public string ContextName() => _context.First(x => x.Metadata["EFContext"].Equals("Other")).Value.GetType().Name;
}

您应该能够将它们与非强类型元数据一起使用，如下所示：

var builder = new ContainerBuilder();                
        builder
            .RegisterType<MyContext>()
            .As<DbContext>()
            .WithMetadata("EFContext", "My");
        builder
            .RegisterType<MyRepository>()
            .AsImplementedInterfaces();

        builder
            .RegisterType<MyOtherContext>()
            .As<DbContext>()
            .WithMetadata("EFContext", "Other");
        builder
            .RegisterType<MyOtherRepository>()
            .AsImplementedInterfaces();

public class SomeClass
{
    private readonly IMyRepository _myRepository;
    private readonly IMyOtherRepository _myOtherRepository;

    public SomeClass(IMyRepository myRepository, IMyOtherRepository myOtherRepository)
    {
        _myRepository = myRepository;
        _myOtherRepository = myOtherRepository;
    }

    public string SayHello()
    {
        return $"Hello from {_myRepository.ContextName()}  and {_myOtherRepository.ContextName()}";
    }
}

public interface IMyOtherRepository
{
    string ContextName();
}

public interface IMyRepository
{
    string ContextName();
}

public class MyContext : DbContext
{
    // Code
}

public class MyOtherContext : DbContext
{
    // Code
}

public class MyRepository : IMyRepository
{
    private readonly IEnumerable<Meta<DbContext>> _context;

    public MyRepository(IEnumerable<Meta<DbContext>> context)
    {
        _context = context;
        // Code
    }

    public string ContextName() => _context.First(x => x.Metadata["EFContext"].Equals("My")).Value.GetType().Name;
}

public class MyOtherRepository : IMyOtherRepository
{
    private readonly IEnumerable<Meta<DbContext>> _context;

    public MyOtherRepository(IEnumerable<Meta<DbContext>> context)
    {
        this._context = context;
        // Code
    }

    public string ContextName() => _context.First(x => x.Metadata["EFContext"].Equals("Other")).Value.GetType().Name;
}

试试这个。基本上，您正在寻找Autofac的功能。我更喜欢

因此，如果您注册这样的上下文：

var builder = new ContainerBuilder();                
        builder
            .RegisterType<MyContext>()
            .As<DbContext>()
            .WithMetadata("EFContext", "My");
        builder
            .RegisterType<MyRepository>()
            .AsImplementedInterfaces();

        builder
            .RegisterType<MyOtherContext>()
            .As<DbContext>()
            .WithMetadata("EFContext", "Other");
        builder
            .RegisterType<MyOtherRepository>()
            .AsImplementedInterfaces();

public class SomeClass
{
    private readonly IMyRepository _myRepository;
    private readonly IMyOtherRepository _myOtherRepository;

    public SomeClass(IMyRepository myRepository, IMyOtherRepository myOtherRepository)
    {
        _myRepository = myRepository;
        _myOtherRepository = myOtherRepository;
    }

    public string SayHello()
    {
        return $"Hello from {_myRepository.ContextName()}  and {_myOtherRepository.ContextName()}";
    }
}

public interface IMyOtherRepository
{
    string ContextName();
}

public interface IMyRepository
{
    string ContextName();
}

public class MyContext : DbContext
{
    // Code
}

public class MyOtherContext : DbContext
{
    // Code
}

public class MyRepository : IMyRepository
{
    private readonly IEnumerable<Meta<DbContext>> _context;

    public MyRepository(IEnumerable<Meta<DbContext>> context)
    {
        _context = context;
        // Code
    }

    public string ContextName() => _context.First(x => x.Metadata["EFContext"].Equals("My")).Value.GetType().Name;
}

public class MyOtherRepository : IMyOtherRepository
{
    private readonly IEnumerable<Meta<DbContext>> _context;

    public MyOtherRepository(IEnumerable<Meta<DbContext>> context)
    {
        this._context = context;
        // Code
    }

    public string ContextName() => _context.First(x => x.Metadata["EFContext"].Equals("Other")).Value.GetType().Name;
}

您应该能够将它们与非强类型元数据一起使用，如下所示：

var builder = new ContainerBuilder();                
        builder
            .RegisterType<MyContext>()
            .As<DbContext>()
            .WithMetadata("EFContext", "My");
        builder
            .RegisterType<MyRepository>()
            .AsImplementedInterfaces();

        builder
            .RegisterType<MyOtherContext>()
            .As<DbContext>()
            .WithMetadata("EFContext", "Other");
        builder
            .RegisterType<MyOtherRepository>()
            .AsImplementedInterfaces();

public class SomeClass
{
    private readonly IMyRepository _myRepository;
    private readonly IMyOtherRepository _myOtherRepository;

    public SomeClass(IMyRepository myRepository, IMyOtherRepository myOtherRepository)
    {
        _myRepository = myRepository;
        _myOtherRepository = myOtherRepository;
    }

    public string SayHello()
    {
        return $"Hello from {_myRepository.ContextName()}  and {_myOtherRepository.ContextName()}";
    }
}

public interface IMyOtherRepository
{
    string ContextName();
}

public interface IMyRepository
{
    string ContextName();
}

public class MyContext : DbContext
{
    // Code
}

public class MyOtherContext : DbContext
{
    // Code
}

public class MyRepository : IMyRepository
{
    private readonly IEnumerable<Meta<DbContext>> _context;

    public MyRepository(IEnumerable<Meta<DbContext>> context)
    {
        _context = context;
        // Code
    }

    public string ContextName() => _context.First(x => x.Metadata["EFContext"].Equals("My")).Value.GetType().Name;
}

public class MyOtherRepository : IMyOtherRepository
{
    private readonly IEnumerable<Meta<DbContext>> _context;

    public MyOtherRepository(IEnumerable<Meta<DbContext>> context)
    {
        this._context = context;
        // Code
    }

    public string ContextName() => _context.First(x => x.Metadata["EFContext"].Equals("Other")).Value.GetType().Name;
}

---

感谢@Sakis的详细而及时的回复，成功了！太棒了，完成了！你介意接受它作为回答吗是的，我现在做了，很抱歉没有早点做，有点新鲜，再次感谢！感谢@Sakis的详细而及时的回复，成功了！太棒了，完成了！你介意接受它作为回答吗是的，我现在做了，很抱歉没有早点做，有点新鲜，再次感谢！