C# c json格式太复杂

有没有办法使这些数据变得简单，这样我就不需要创建7次来显示不同的日期。以及如何在C中显示所有这些数据。

尝试如下：

[
    {
        "Location": "St Kilda",
        "Name": "Movie Plaza theatre",
        "Day": "Monday",
        "Session": [
                    { "Moive": "Ant-man", "Time": "11 am", "Seat": 20 },
                    { "Moive": "Bat-man", "Time": "12 pm", "Seat": 20 },
                    { "Moive": "Spider-man", "Time": "1 pm", "Seat": 20 },
                    { "Moive": "Super-man", "Time": "2 pm", "Seat": 20 },
                    { "Moive": "DeadPool", "Time": "3 pm", "Seat": 20 }
                  ]
    },
     {
        "Location": "St Kilda",
        "Name": "Movie Plaza theatre",
        "Day": "Tuesday",
        "Session": [
                    { "Moive": "Ant-man", "Time": "11 am", "Seat": 20 },
                    { "Moive": "Bat-man", "Time": "12 pm", "Seat": 20 },
                    { "Moive": "Spider-man", "Time": "1 pm", "Seat": 20 },
                    { "Moive": "Super-man", "Time": "2 pm", "Seat": 20 },
                    { "Moive": "DeadPool", "Time": "3 pm", "Seat": 20 }
                  ]
   }
]

然后，您可以通过obj迭代操作数据

---

然后，您还需要对其进行迭代，因为它也是一个列表。

static void PrintDataList data{foreach var item in data{Console.WriteLineitem.Location+item.Name+item.Day；foreach var u in item.Session{Console.WriteLineu；}}}}我无法在会话中获得值，我得到的是Moss.Session 5次。再次在item.Session{Console.writesession.Movie；}中像foreachvar会话那样执行，它将在数据中工作{Console.WriteLineitem.Location+item.Name+item.Day；item.Session中的foreach var u{Console.writelineeu.Movie；}我这样做了，但我只能得到5个空插槽

    public class Session
    {
        public string Moive { get; set; }
        public string Time { get; set; }
        public int Seat { get; set; }
    }

    public class RootObject
    {
        public string Location { get; set; }
        public string Name { get; set; }
        public string Day { get; set; }
        public List<Session> Session { get; set; }
    }

    var obj = JsonConvert.DeserializeObject<List<RootObject>>(json);