C# 从其他列表中排除包含值的列表项
有两个列表:C# 从其他列表中排除包含值的列表项,c#,.net,linq,filtering,C#,.net,Linq,Filtering,有两个列表: List<string> excluded = new List<string>() { ".pdf", ".jpg" }; List<string> dataset = new List<string>() {"valid string", "invalid string.pdf", "invalid string2.jpg","valid string 2.xml" }; List excluded=newlist(){.pdf
List<string> excluded = new List<string>() { ".pdf", ".jpg" };
List<string> dataset = new List<string>() {"valid string", "invalid string.pdf", "invalid string2.jpg","valid string 2.xml" };
List excluded=newlist(){.pdf',.jpg};
列表数据集=新列表(){“有效字符串”、“无效字符串.pdf”、“无效字符串2.jpg”、“有效字符串2.xml”};
如何从“数据集”列表中筛选出包含“排除”列表中任何关键字的值?尝试:
当排除列表为空时,此选项也有效
// Contains four values.
int[] values1 = { 1, 2, 3, 4 };
// Contains three values (1 and 2 also found in values1).
int[] values2 = { 1, 2, 5 };
// Remove all values2 from values1.
var result = values1.Except(values2);
var result=dataset.Where(x=>!excluded.Contains(x)) 正如abatishchev所说,将
排除在外
设置为哈希集
,特别是如果它很大的话。谢谢。如果我们在HashSets,我将提供这个链接来讨论这个主题:在列表中找不到包含?@Choco:usingsystem.Linq;
var result = from s in dataset
from e in excluded
where !s.Contains(e)
select e;
var result=dataset.Where(x=>!excluded.Exists(y=>x.Contains(y)));
// Contains four values.
int[] values1 = { 1, 2, 3, 4 };
// Contains three values (1 and 2 also found in values1).
int[] values2 = { 1, 2, 5 };
// Remove all values2 from values1.
var result = values1.Except(values2);