Database 我在SQL炼金术中的关系有什么问题？

我正在使用SQLAlchemy和Flask为我的应用程序创建关系。我最近重写了这些关系，无论我做了什么改变，我总是会出错：

sqlalchemy.exc.NoForeignKeysError: Could not determine join condition between 
parent/child tables on relationship CurriculumVersion.enrollments - there are 
no foreign keys linking these tables.  Ensure that referencing columns are 
associated with a ForeignKey or ForeignKeyConstraint, or specify
a 'primaryjoin' expression.

在我的模型上：

class User(db.Model, AuthUser):
    id = db.Column(db.Integer, primary_key=True)
    tf_login = db.Column(db.String(255), unique=True, nullable=False) # can assume is an email
    password = db.Column(db.String(120), nullable=False)
    salt = db.Column(db.String(80))
    role = db.Column(db.String(80)) # for later when have different permission types
    zoho_contactid = db.Column(db.String(20), unique=True, nullable=False)
    created_asof = db.Column(db.DateTime, default=datetime.datetime.utcnow)
    enrollments = db.relationship('Enrollment', backref='enrollment', lazy='dynamic')
    firstname = db.Column(db.String(80))
    lastname = db.Column(db.String(80))


    def __repr__(self):
        return '#%d tf_login: %s, First Name: %s Last Name: %s created_asof %s' % (self.id, self.tf_login, self.firstname, self.lastname, self.created_asof)

    def __getstate__(self):
        return {
            'id': self.id,
            'tf_login': self.tf_login,
            'firstname': self.firstname,
            'lastname': self.lastname,
            'role': self.role,
            'created_asof': self.created_asof,
        }

    @classmethod
    def load_current_user(cls, apply_timeout=True):
        data = get_current_user_data(apply_timeout)
        if not data:
            return None
        return cls.query.filter(cls.email==data['email']).one()
        return '#%d Course Name: %s, Course Version: %s, Closing Date: %s' %(self.id, self.course_name, self.course_version, self.closing_date)

class Enrollment(db.Model, AuthUser):
    id = db.Column(db.Integer, primary_key=True)
    user_id = db.Column(db.Integer, db.ForeignKey('user.id'))
    version_id = db.Column(db.Integer, db.ForeignKey('curriculumversion.id'))
    cohort_id = db.Column(db.Integer, db.ForeignKey('cohort.id'))

    def __repr__(self):
        return '#%d User ID: %d Version ID: %d, Cohort ID: %d' %(self.id, self.user_id, self.version_id, self.cohort_id)

class Cohort(db.Model, AuthUser):
    id = db.Column(db.Integer, primary_key=True)
    days_to_completion = db.Column(db.String(20))
    course_id = db.Column(db.Integer, db.ForeignKey('course.id'))
    enrollments = db.relationship('Enrollment', backref='enrollment', lazy='dynamic')

    def __repr__(self):
        return '#%d Days To Completion: %s' %(self.id, self.days_to_completion)


class CurriculumVersion(db.Model, AuthUser):
    id = db.Column(db.Integer, primary_key=True)
    version_number = db.Column(db.String(6))
    date_implemented = db.Column(db.DateTime)
    course_id = db.Column(db.Integer, db.ForeignKey('course.id'))
    enrollments = db.relationship('Enrollment', backref='enrollment', lazy='dynamic')

    def __repr__(self):
        return '#%d Version Number: %s, Date Implemented: %s' %(self.id, self.version_number, self.date_implemented)

class Course(db.Model, AuthUser):
    id = db.Column(db.Integer, primary_key=True)
    course_code = db.Column(db.String(20))
    course_name = db.Column(db.String(50))
    versions = db.relationship('CurriculumVersion', backref='version', lazy='dynamic')
    cohorts = db.relationship('Cohort', backref='cohort', lazy='dynamic')


    def __repr__(self):
        return '#%d Course Code: %s, Course Name: %s' %(self.id, self.course_code, self.course_name)

---

任何帮助都将不胜感激

尝试在课程版本课程中使用primaryjoin，如下所示：

改变

enrollments = db.relationship('Enrollment', backref='enrollment', lazy='dynamic')

到

注意：您可能还需要对其他类执行此操作。

此错误：

Could not determine join condition between parent/child tables on relationship CurriculumVersion.enrollments 

意味着SQLAlchemy无法在

注册中找到合适的列作为关系中的外键

您定义了外键，但使用了不正确的表名。Flask SQLAlchemy在创建表时将
CamelCase
类转换为
camel\u case
，因此您需要更改：

class Enrollment(db.Model, AuthUser):
    # ...
    version_id = db.Column(db.Integer, db.ForeignKey('curriculumversion.id'))
    #...

为此：

class Enrollment(db.Model, AuthUser):
    # ...
    version_id = db.Column(db.Integer, db.ForeignKey('curriculum_version.id'))
    #...

或者，您可以使用
\uuuu tablename\uuuu
属性来覆盖Flask SQLAlchemy使用的默认命名约定。
这会显示错误消息：“sqlalchemy.exc.NorReferencedTableError:与列'enrollment.version_id'关联的外键找不到表'CoursulumVersion'，无法使用该表生成指向目标列'id'的外键”“有什么想法吗？您的示例中缺少了修复此问题的详细信息-示例中的ForeignKey指的是'CoursulumVersion.id'，但出于某种原因，它正在寻找一个名为“CoursulumVersion”的表-db.Model到底做了什么，
\uuuuuuTableName\uuuuuuuuu
，等等？这真的让我很生气。”。知道为什么会这样吗？因为Flask认为为您创建名称，而不是让开发人员显式地生成这些约定，会让您的生活更轻松。SQLAlchemy本身从不产生任何形式的约定，只是提供了一些工具来创建自己的约定。
class Enrollment(db.Model, AuthUser):
    # ...
    version_id = db.Column(db.Integer, db.ForeignKey('curriculum_version.id'))
    #...