如何更新Db2表行并删除现有行？

DB2表ZB_BILL_ERR:

PROCESS_DATE    CURR_PROCESS_DT  ACCOUNT_NUMBER  SEQ_NUM    ERROR_REASON 
07/14/2013  07/14/2013  A123456789    1     Trancode Invalid
07/15/2013  07/15/2013  B987654321    1     Adjustment code invalid
07/16/2013  07/16/2013  A123456789    2     Multi Single ind invalid

预期产出：

PROCESS_DATE    CURR_PROCESS_DT  ACCOUNT_NUMBER  SEQ_NUM    ERROR_REASON 
07/15/2013  07/15/2013   B987654321   1     Adjustment code invalid
07/14/2013  07/16/2013  A123456789    2     Multi Single ind invalid

---

A123456789最新一行的处理日期将具有表中账户最早的处理日期，在本例中为2013年7月14日，并删除A123456789最早的一行。要识别最新记录，请使用

  row_number() over (partition by account_number
                     order by curr_processs_dt descending
                    ) as aging

这将在帐户中按降序排列您的行。选择aging=1的行以获取最新的

要获取帐户的最早日期，请执行以下操作：

select account_number, min(process_dt) as first_processed
  from input
  group by account_number

因此，让我们将其合并到一个（有点复杂的）SQL语句中

MERGE into ZB_BILL_ERR m
USING ( 
        with g as
        (
          select account_number
               , min(process_dt) as first_processed
            from ZB_BILL_ERR 
            group by account_number 
        )
        select i.*
             , row_number() over (partition by account_number
                                    order by curr_processs_dt descending
                                   ) as aging
             , first_processed
            from g
            join ZB_BILL_ERR i  on i.account_number = g.account_number
      ) as x
  ON m.account_number = x.accout_number
  WHEN MATCHED and x.aging = 1  THEN
    UPDATE process_dt = x.first_processed
  WHEN MATCHED and x.aging > 1  THEN
    DELETE
;

---

... 如果可能的话（每个id只需要一行），我首先在

A123456789

上使表唯一，然后在过程中更新或插入，或者使用

MERGE

语句（如果您的DB2版本支持）。到目前为止，您尝试了什么版本的DB2？