Django rest framework 如何在django中使QueryDict实例可变

我有一个序列化类，如下所示：

class EmployeeSerializer(serializers.ModelSerializer):
    # TODO: Define serializer fields here
    bio = BioSerializer()
    designation = GroupListSerializer()
    department = GroupListSerializer()
    #user = UserSerializer()
    class Meta:
        model = Employee
        fields = '__all__'
        # fields = ['user','tax_id_number','account_number','joining_date','designation','department','gender','marital_status','id_type','birthday','ethnicity','preferred_language','phone_number','em_contact','address']


    def create(self,validated_data):
        bio = validated_data.pop('bio')
        designation = validated_data.pop('designation')
        department = validated_data.pop('department')

        new_bio = Bio.objects.create(**bio)

        new_designation = Groups.objects(**designation) 
        new_department = Groups.objects(**department)
        employee = list(Employee.objects.create(designation=new_designation,department=new_department,
                    bio=new_bio,**validated_data))
        employee = json.dumps(employee)
        return employee

我的观点如下：

class EmployeeRecordView(generics.CreateAPIView):
    queryset=Employee.objects.all()
    serializer_class=EmployeeSerializer

    def post(self, request):

        serializer = EmployeeSerializer(data=request.data)
        if serializer.is_valid(raise_exception=ValueError):
            serializer.create(validated_data=request.data)
            return Response(serializer.data, status=status.HTTP_201_CREATED)
        return Response(serializer.error_messages,
                        status=status.HTTP_400_BAD_REQUEST)

问题是，当我尝试发出“POST”请求时，我会得到以下日志：

Exception Type: AttributeError
Exception Value:    
This QueryDict instance is immutable

---

如何使

POST

ing成功。我在上面实现的这种方法哪里出了问题？

你不应该调用

序列化程序。自己创建
我相信引发错误的那一行是
序列化程序。创建（已验证的数据=请求.数据）
。您可以尝试以下方法：

...
serializer.is_valid(raise_exception=True)
serializer.save()
return Response(serializer.data, status=status.HTTP_201_CREATED)

另一件事是，当您设置
raise\u exception=True
时，它已经抛出一个错误响应，因此您不需要将其放入
if/else
块中