使用Django和Python 3检测移动设备

使用Django和Python 3检测移动设备,django,python-3.x,user-agent,mobile-website,Django,Python 3.x,User Agent,Mobile Website,在Django视图中,我正在努力找到一种简单的方法来检测请求是否来自移动设备 我正在尝试实现如下内容: #views.py def myfunction(request): ... if request.mobile: is_mobile = True else: is_mobile = False context = { ... , 'is_mobile': is_mobile, }

在Django视图中,我正在努力找到一种简单的方法来检测请求是否来自移动设备

我正在尝试实现如下内容:

#views.py

def myfunction(request):

    ...
    if request.mobile:
        is_mobile = True
    else:
        is_mobile = False

    context = {
        ... ,
        'is_mobile': is_mobile,
    }
    return render(request, 'mytemplate.html', context)
mytemplate.html
中:

{% if is_mobile %}    
    show something
{% else %}
    show something else
{% endif %}
我检查过的任何地方(例如或)都是推荐的。我已经安装了不同的版本:
pip install minidetector
pip install minidetector 2
,还直接安装了两个github存储库,但没有一个与Python 3兼容

因此,我的问题是:是否有与Python3兼容的minidetector版本/分支?如果没有,有什么替代方案?

包与Python 3兼容

按照上面提供的链接中的安装说明进行操作,然后您可以按如下方式使用它:

def my_view(request):

    # Let's assume that the visitor uses an iPhone...
    request.user_agent.is_mobile # returns True
    request.user_agent.is_tablet # returns False
    request.user_agent.is_touch_capable # returns True
    request.user_agent.is_pc # returns False
    request.user_agent.is_bot # returns False

    # Accessing user agent's browser attributes
    request.user_agent.browser  # returns Browser(family=u'Mobile Safari', version=(5, 1), version_string='5.1')
    request.user_agent.browser.family  # returns 'Mobile Safari'
    request.user_agent.browser.version  # returns (5, 1)
    request.user_agent.browser.version_string   # returns '5.1'

    # Operating System properties
    request.user_agent.os  # returns OperatingSystem(family=u'iOS', version=(5, 1), version_string='5.1')
    request.user_agent.os.family  # returns 'iOS'
    request.user_agent.os.version  # returns (5, 1)
    request.user_agent.os.version_string  # returns '5.1'

    # Device properties
    request.user_agent.device  # returns Device(family='iPhone')
    request.user_agent.device.family  # returns 'iPhone'
{% if request.user_agent.is_mobile %}
    Do stuff here...
{% endif %}
模板中的用法如下所示:

def my_view(request):

    # Let's assume that the visitor uses an iPhone...
    request.user_agent.is_mobile # returns True
    request.user_agent.is_tablet # returns False
    request.user_agent.is_touch_capable # returns True
    request.user_agent.is_pc # returns False
    request.user_agent.is_bot # returns False

    # Accessing user agent's browser attributes
    request.user_agent.browser  # returns Browser(family=u'Mobile Safari', version=(5, 1), version_string='5.1')
    request.user_agent.browser.family  # returns 'Mobile Safari'
    request.user_agent.browser.version  # returns (5, 1)
    request.user_agent.browser.version_string   # returns '5.1'

    # Operating System properties
    request.user_agent.os  # returns OperatingSystem(family=u'iOS', version=(5, 1), version_string='5.1')
    request.user_agent.os.family  # returns 'iOS'
    request.user_agent.os.version  # returns (5, 1)
    request.user_agent.os.version_string  # returns '5.1'

    # Device properties
    request.user_agent.device  # returns Device(family='iPhone')
    request.user_agent.device.family  # returns 'iPhone'
{% if request.user_agent.is_mobile %}
    Do stuff here...
{% endif %}

但是,请注意,Django 1.10中的中间件类已经更改。因此,如果您使用的是Django 1.10+,则必须修改此包中的中间件类定义,如下所示。

我找到了另一种方法,从

通过在
views.py中添加一个附加函数

import re

def mobile(request):
"""Return True if the request comes from a mobile device."""

    MOBILE_AGENT_RE=re.compile(r".*(iphone|mobile|androidtouch)",re.IGNORECASE)

    if MOBILE_AGENT_RE.match(request.META['HTTP_USER_AGENT']):
        return True
    else:
        return False


def myfunction(request):

    ...
    if mobile(request):
        is_mobile = True
    else:
        is_mobile = False

    context = {
        ... ,
        'is_mobile': is_mobile,
    }
    return render(request, 'mytemplate.html', context)

您已链接到一个不相关的属性错误问题。张贴StackTrace链接旨在显示minidetector与Python 3不兼容。为了避免对问题本身产生任何混淆,我已将其删除并重新表述了该部分。我建议检查一下