使用Vue.js、Axios和Django筛选对象
我有一个Vue.js和Django的项目。我试图通过简单的搜索从数据库中获取一个列表。在Vue/Axios中,我有:使用Vue.js、Axios和Django筛选对象,django,vue.js,axios,Django,Vue.js,Axios,我有一个Vue.js和Django的项目。我试图通过简单的搜索从数据库中获取一个列表。在Vue/Axios中,我有: var food = 'CHICKEN' const url = `${API_URL}/api/list_food_composition/${food}`; axios.get(url).then(response => { var data = response.data; console.log(data) }); 但响应是“未定义的” 在
var food = 'CHICKEN'
const url = `${API_URL}/api/list_food_composition/${food}`;
axios.get(url).then(response => {
var data = response.data;
console.log(data)
});
但响应是“未定义的”
在Django,我有:
url.py
url(r'^api/list_food_composition/$', views.list_food_composition),
views.py
def list_food_composition(request,food):
foods = Food_composition.objects.filter(short_description__contains=food)
data = serializers.serialize('json', foods)
return HttpResponse(data, content_type='application/json')
正确的方法是什么?请按如下方式更新您的视图:
from django.http import JsonResponse
def list_food_composition(request,food):
foods = Food_composition.objects.filter(short_description__contains=food)
data = serializers.serialize('json', foods)
return JsonResponse({'data': data}, content_type='application/json')
而URL应该是:
url(r'^api/list_food_composition/(?P<food>\w+)$', views.list_food_composition),
url(r'^api/list\u food\u composition/(?P\w+)$,views.list\u food\u composition),
console.log(响应)提供了什么?以粗体显示。It响应“未定义”