Django 如何使新的DRF 3.6内置文档正常工作?
我尝试设置新的Django Rest框架内置文档,遵循(异常简洁的)命令 现在,我得到一个带有401未经授权错误的页面,并且我看不到我的端点。当单击会话身份验证时,我得到下面的消息 但是,我已经在另一个选项卡中以超级用户身份登录了会话 以下是我目前掌握的代码: url.pyDjango 如何使新的DRF 3.6内置文档正常工作?,django,django-rest-framework,Django,Django Rest Framework,我尝试设置新的Django Rest框架内置文档,遵循(异常简洁的)命令 现在,我得到一个带有401未经授权错误的页面,并且我看不到我的端点。当单击会话身份验证时,我得到下面的消息 但是,我已经在另一个选项卡中以超级用户身份登录了会话 以下是我目前掌握的代码: url.py root_urlpatterns = [ url(r'^api/v', include('api.urls', namespace='api')), # Api endpoints url(r'^admi
root_urlpatterns = [
url(r'^api/v', include('api.urls', namespace='api')), # Api endpoints
url(r'^admin/', admin.site.urls, name="admin"), # Admin
url(r'^docs/', include_docs_urls(title='My API')), # Built-in DRF documentation
]
urlpatterns = [
url(r'^backend/', include(root_urlpatterns))
]
endpoints_urlpatterns = [
url(regex=r'^customers/activate/$',
view=views_customer.ActivateCustomerView.as_view(),
name="activate-customer"),
]
VERSION = 1
urlpatterns = [
url(r'^{}/'.format(VERSION), include(endpoints_urlpatterns))
]
api/url.py
root_urlpatterns = [
url(r'^api/v', include('api.urls', namespace='api')), # Api endpoints
url(r'^admin/', admin.site.urls, name="admin"), # Admin
url(r'^docs/', include_docs_urls(title='My API')), # Built-in DRF documentation
]
urlpatterns = [
url(r'^backend/', include(root_urlpatterns))
]
endpoints_urlpatterns = [
url(regex=r'^customers/activate/$',
view=views_customer.ActivateCustomerView.as_view(),
name="activate-customer"),
]
VERSION = 1
urlpatterns = [
url(r'^{}/'.format(VERSION), include(endpoints_urlpatterns))
]
所有必需的软件包(coreapi、Pygments、markdown)都已安装pip。
有什么想法吗?非常感谢。确保也有SessionAuthentication:
REST_FRAMEWORK = {
'DEFAULT_AUTHENTICATION_CLASSES': (
'rest_framework.authentication.TokenAuthentication',
'rest_framework.authentication.SessionAuthentication',
),
您可以同时添加权限类和身份验证类吗?您是对的,这就是问题所在:
SessionAuthentication
在DEFAULT\u Authentication\u class
设置列表中缺少。谢谢