Django批注无法使用order_by
我想在('-end_date')之前获得MyModel order_的最后100条记录,并对不同的赢家类型进行总和注释Django批注无法使用order_by,django,django-models,Django,Django Models,我想在('-end_date')之前获得MyModel order_的最后100条记录,并对不同的赢家类型进行总和注释 MyModel.objects.all()[:100].order_by('-end_game_time').values('winner').annotate(total=Count('winner')) 结果查询如下,我没有预期的组 <QuerySet [{'winner': 3, 'total': 1}, {'winner': 15, 'total': 1}, '
MyModel.objects.all()[:100].order_by('-end_game_time').values('winner').annotate(total=Count('winner'))
结果查询如下,我没有预期的组
<QuerySet [{'winner': 3, 'total': 1}, {'winner': 15, 'total': 1}, 'total': 1}, {'winner': 3, 'total': 1}, {'winner': 5, 'total': 1}, {'winner': 15, 'total': 1}, {'winner': 5, 'total': 1}, {'winner': 3, 'total': 1}, '...(remaining elements truncated)...']>
但是当我没有订单时,结果正如我所预料的
MyModel.objects.all()[:100].values('winner').annotate(total=Count('winner'))
Out[52]: <QuerySet [{'winner': 5, 'total': 43}, {'winner': 1, 'total': 2}, {'winner': 15, 'total': 51}, {'winner': 2, 'total': 42}, {'winner': 3, 'total': 43}]>
据我所知,不可能在单个查询中实现您想要做的事情,您想要在SQL中实现的是:
SELECT "game_mymodel"."winner", COUNT("game_mymodel"."winner") AS "total" FROM "game_mymodel" GROUP BY "game_mymodel"."winner" ORDER BY "game_mymodel"."end_game_time" DESC LIMIT 100
这不是一个有效的sql查询,因此您需要有一个子查询来选择100个元素,然后对它们应用聚合
首先构建子查询:
top_100_games = MyModel.objects.order_by('-end_game_time')[:100].only('id').all()
然后在主查询中使用它:
MyModel.objects.filter(id__in=top_100_games).values('winner').annotate(total=Count('winner'))
top_100_games = MyModel.objects.order_by('-end_game_time')[:100].only('id').all()
MyModel.objects.filter(id__in=top_100_games).values('winner').annotate(total=Count('winner'))