测试django tastypie时遇到的问题
我在这里举一个例子: My URL.py:测试django tastypie时遇到的问题,django,tastypie,Django,Tastypie,我在这里举一个例子: My URL.py: from django.conf.urls import patterns, include, url from django.contrib import admin from django.conf.urls.defaults import * from ristoturisto.api import EntryResource entry_resource = EntryResource() admin.autodiscover() urlp
from django.conf.urls import patterns, include, url
from django.contrib import admin
from django.conf.urls.defaults import *
from ristoturisto.api import EntryResource
entry_resource = EntryResource()
admin.autodiscover()
urlpatterns = patterns('',
url(r'^admin/', include(admin.site.urls)),
(r'^blog/', include('ristoturisto.urls')), #this basically points to it self?
(r'^api/', include(EntryResource.urls)),
)
api.py
from tastypie.resources import ModelResource
from locations.models import tours
class EntryResource(ModelResource):
class Meta:
queryset = tours.objects.all()
resource_name = 'Tours'
型号:
class tours(models.Model):
name = models.CharField(max_length=255)
categories = models.ForeignKey('categories')
icon = models.CharField(max_length=255)
publishdate = models.CharField(max_length=255)
locations = models.ManyToManyField('geolocations')
我得到的错误是:
at/api/tours配置不当
当我尝试访问时:http://127.0.0.1:8000/api/tours?format=json
实体资源从何处获取其URL?它不在示例中?您使用类EntryResource而不是该类的实例entry\u resource:
(r'^api/', include(EntryResource.urls)),
更改它:
(r'^api/', include(entry_resource.urls)),
天哪,你是对的!我现在有一个新的错误,但谢谢你在这两天里一直在研究。。。先生,你是一位真正的绅士!你使用代码检查器吗?我使用flake8,它会在类似这样的情况下通知我(例如,变量未使用)。