如何在django模型中填充字段
我有一个Django项目,其中有一个子类来自Django如何在django模型中填充字段,django,django-models,django-views,Django,Django Models,Django Views,我有一个Django项目,其中有一个子类来自DjangoCreateView类的视图。此视图用于将文件上载到服务器,并使用我创建的UploadedFile模型。上载的文件也需要与项目关联 项目id作为URL的一部分传入:(r'^projects/(?p\d+/$),UploadedFileCreateView.as_view(),{},'upload new') 问题是,我不确定将此键与我的型号关联的适当位置。是否有一个CreateView方法或它的一个祖先,我应该重写它来创建模型,或者这可以在
CreateView
类的视图。此视图用于将文件上载到服务器,并使用我创建的UploadedFile
模型。上载的文件也需要与项目关联
项目id作为URL的一部分传入:(r'^projects/(?p\d+/$),UploadedFileCreateView.as_view(),{},'upload new')
问题是,我不确定将此键与我的型号关联的适当位置。是否有一个CreateView
方法或它的一个祖先,我应该重写它来创建模型
,或者这可以在我的代码中的任何地方用我已经重写过的方法之一来完成(尽管这感觉有点粗糙)
此外,myUploadedFile
的project
属性被定义为类型为project
的ForeignKey
。如何使项目
与之关联
这是我的模型
定义:
class Project(models.Model):
"""This is a project that is owned by a user and contains many UploadedFiles."""
name = models.CharField(max_length=200)
class UploadedFile(models.Model):
"""This represents a file that has been uploaded to the server."""
STATE_UPLOADED = 0
STATE_ANNOTATED = 1
STATE_PROCESSING = 2
STATE_PROCESSED = 4
STATES = (
(STATE_UPLOADED, "Uploaded"),
(STATE_ANNOTATED, "Annotated"),
(STATE_PROCESSING, "Processing"),
(STATE_PROCESSED, "Processed"),
)
status = models.SmallIntegerField(choices=STATES,
default=0, blank=True, null=True)
file = models.FileField(upload_to=settings.XML_ROOT)
project = models.ForeignKey(Project)
def __unicode__(self):
return self.file.name
def name(self):
return os.path.basename(self.file.name)
def save(self, *args, **kwargs):
if not self.status:
self.status = self.STATE_UPLOADED
super(UploadedFile, self).save(*args, **kwargs)
def delete(self, *args, **kwargs):
os.remove(self.file.path)
self.file.delete(False)
super(UploadedFile, self).delete(*args, **kwargs)
class UploadedFileCreateView(CreateView):
model = UploadedFile
def form_valid(self, form):
logger.critical("Inside form_valid")
self.object = form.save()
f = self.request.FILES.get('file')
data = [{'name': f.name,
'url': settings.MEDIA_URL + "files/" + f.name.replace(" ", "_"),
'project': self.object.project.get().pk,
'delete_url': reverse('fileupload:upload-delete',
args=[self.object.id]),
'delete_type': "DELETE"}]
response = JSONResponse(data, {}, response_mimetype(self.request))
response['Content-Disposition'] = 'inline; filename=files.json'
return super(UploadedFileCreateView, self).form_valid(form)
def get_context_data(self, **kwargs):
context = super(UploadedFileCreateView, self).get_context_data(**kwargs)
return context
以下是我的视图定义:
class Project(models.Model):
"""This is a project that is owned by a user and contains many UploadedFiles."""
name = models.CharField(max_length=200)
class UploadedFile(models.Model):
"""This represents a file that has been uploaded to the server."""
STATE_UPLOADED = 0
STATE_ANNOTATED = 1
STATE_PROCESSING = 2
STATE_PROCESSED = 4
STATES = (
(STATE_UPLOADED, "Uploaded"),
(STATE_ANNOTATED, "Annotated"),
(STATE_PROCESSING, "Processing"),
(STATE_PROCESSED, "Processed"),
)
status = models.SmallIntegerField(choices=STATES,
default=0, blank=True, null=True)
file = models.FileField(upload_to=settings.XML_ROOT)
project = models.ForeignKey(Project)
def __unicode__(self):
return self.file.name
def name(self):
return os.path.basename(self.file.name)
def save(self, *args, **kwargs):
if not self.status:
self.status = self.STATE_UPLOADED
super(UploadedFile, self).save(*args, **kwargs)
def delete(self, *args, **kwargs):
os.remove(self.file.path)
self.file.delete(False)
super(UploadedFile, self).delete(*args, **kwargs)
class UploadedFileCreateView(CreateView):
model = UploadedFile
def form_valid(self, form):
logger.critical("Inside form_valid")
self.object = form.save()
f = self.request.FILES.get('file')
data = [{'name': f.name,
'url': settings.MEDIA_URL + "files/" + f.name.replace(" ", "_"),
'project': self.object.project.get().pk,
'delete_url': reverse('fileupload:upload-delete',
args=[self.object.id]),
'delete_type': "DELETE"}]
response = JSONResponse(data, {}, response_mimetype(self.request))
response['Content-Disposition'] = 'inline; filename=files.json'
return super(UploadedFileCreateView, self).form_valid(form)
def get_context_data(self, **kwargs):
context = super(UploadedFileCreateView, self).get_context_data(**kwargs)
return context
您可以在调用form.save()
的位置执行此操作。只需传递commit=False
,以便在添加项目id之前不会将其保存到数据库中。例如:
self.object = form.save(commit=False)
self.object.project_id = self.kwargs['proj_key']
self.object.save()
只需确保表单不包含项目字段
编辑:要排除该字段,请将excludes
变量添加到表单元类中:
class UploadedFileForm(forms.ModelForm):
class Meta:
model = UploadedFile
excludes = ('project',)
您可以在调用form.save()
的位置执行此操作。只需传递commit=False
,以便在添加项目id之前不会将其保存到数据库中。例如:
self.object = form.save(commit=False)
self.object.project_id = self.kwargs['proj_key']
self.object.save()
只需确保表单不包含项目字段
编辑:要排除该字段,请将excludes
变量添加到表单元类中:
class UploadedFileForm(forms.ModelForm):
class Meta:
model = UploadedFile
excludes = ('project',)
就目前而言,form.save()
从未执行,因为form\u valid
从未执行-我猜这是因为表单没有正确处理ForeignKey
,但我不确定如何才能做到这一点。正如我所说,您还需要从表单中排除项目字段。否则,它将尝试验证项目是否设置为form\u valid()
。这就是form\u valid()
产生的错误吗?我该怎么做?我需要创建一个上传的文件格式吗?是的,这可能是最简单的方法。我已经更新了我的答案来说明如何做。即使做了这些更改,django似乎从未进入form\u valid
方法,JSON请求会导致SyntaxError:Unexpected token,就像现在一样,form.save()
从不执行,因为form\u valid
从不执行-我猜这是因为表单没有正确处理ForeignKey
,但我不确定如何才能做到这一点。正如我所说,您还需要从表单中排除项目字段。否则,它将尝试验证项目是否设置为form\u valid()
。这就是form\u valid()
产生的错误吗?我该怎么做?我需要创建一个上传的文件格式吗?是的,这可能是最简单的方法。我已经更新了我的答案来说明如何做。即使有了这些更改,django似乎从未进入form\u valid
方法,JSON请求会导致SyntaxError:Unexpected token