如何路由包含querystring的DooPHP URI？

我需要能够路由在查询字符串中传递信息的请求。例如，假设我的应用程序调用/api/company/delete？id=17。我如何在DooPHP中传递它？我已经定义了一个catchall路由，它正在捕获这个请求，但是我需要能够在没有catchall路由的情况下处理这些请求

# this doesn't work
$route['get']['/api/company/delete?id=:id'] = array('AdminController', 'deletecompany');

# at the bottom of my routes I have this catchall route, which works but it catches --everything--
$route['*']['catchall']['/:id'] = array('HomeController', 'getregions'); 

我错过了什么明显的东西吗？

$route['get']['/api/company/delete/:id']=array（'AdminController'，'deletecompany'）

控制器 $this->params['id']

或

路线 $route['post']['/api/company/delete']=array（'AdminController'，'deletecompany'）

控制器 $\u POST['id']