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Ecl 关于newlisp中的阶乘_Ecl_Newlisp - Fatal编程技术网

Ecl 关于newlisp中的阶乘

Ecl 关于newlisp中的阶乘,ecl,newlisp,Ecl,Newlisp,我使用ECL和newlisp运行facorial函数 ECL: 纽里斯普 >(define (fac n) (if (= n 1) 1 (* n (fac (- n 1))))) >(fac 20) 22432902008176640000 >(fac 30) -8764578968847253504 为什么newlisp使用ecl返回不同的结果?newlisp中最大的64位整数是9223372036854775807 尝试浮点运算: (define (fac n) (if

我使用ECL和newlisp运行facorial函数

ECL:

纽里斯普

>(define (fac n) (if (= n 1) 1 (* n (fac (- n 1)))))
>(fac 20)
22432902008176640000
>(fac 30)
-8764578968847253504

为什么newlisp使用ecl返回不同的结果?

newlisp中最大的64位整数是9223372036854775807

尝试浮点运算:

(define (fac n) (if (= n 1) 1 (mul n (fac (sub n 1)))))

(fac 20) => 2.432902008e+18

newLISP被设计为小到260K,默认情况下,您不会得到的一件事是支持真正的大整数,以及普通大小和大整数之间必要的自动转换。如果你经常需要像1000这样的整数!在你的工作中,你可能选择了错误的语言。但是,如果您想出于其他原因使用newLISP,并且确实需要计算100!,然后安装GMP库,并按如下方式编写代码:

(load "gmp.lsp")
(define (factorial-gmp num)
 (if (= num 0)
  "1"
  (GMP:* (string num) (factorial-gmp (- num 1)))))

从版本10.4.8开始,newLISP内置了对无限精度整数的bigint支持。这使得GNU GMP模块GMP.lsp过时。但由于bigint的工作方式,您将看到一个与典型递归函数完全不同的阶乘函数:

(define (fac n) (apply * (map bigint (sequence 1 n)) 2))
(fac 1000)

> 
(lambda (n) (apply * (map bigint (sequence 1 n)) 2))
402387260077093773543702433923003985719374864210714632543799910429938512398629020592044208486969404800479988610197196058631666872994808558901323829669944590997424504087073759918823627727188732519779505950995276120874975462497043601418278094646496291056393887437886487337119181045825783647849977012476632889835955735432513185323958463075557409114262417474349347553428646576611667797396668820291207379143853719588249808126867838374559731746136085379534524221586593201928090878297308431392844403281231558611036976801357304216168747609675871348312025478589320767169132448426236131412508780208000261683151027341827977704784635868170164365024153691398281264810213092761244896359928705114964975419909342221566832572080821333186116811553615836546984046708975602900950537616475847728421889679646244945160765353408198901385442487984959953319101723355556602139450399736280750137837615307127761926849034352625200015888535147331611702103968175921510907788019393178114194545257223865541461062892187960223838971476088506276862967146674697562911234082439208160153780889893964518263243671616762179168909779911903754031274622289988005195444414282012187361745992642956581746628302955570299024324153181617210465832036786906117260158783520751516284225540265170483304226143974286933061690897968482590125458327168226458066526769958652682272807075781391858178889652208164348344825993266043367660176999612831860788386150279465955131156552036093988180612138558600301435694527224206344631797460594682573103790084024432438465657245014402821885252470935190620929023136493273497565513958720559654228749774011413346962715422845862377387538230483865688976461927383814900140767310446640259899490222221765904339901886018566526485061799702356193897017860040811889729918311021171229845901641921068884387121855646124960798722908519296819372388642614839657382291123125024186649353143970137428531926649875337218940694281434118520158014123344828015051399694290153483077644569099073152433278288269864602789864321139083506217095002597389863554277196742822248757586765752344220207573630569498825087968928162753848863396909959826280956121450994871701244516461260379029309120889086942028510640182154399457156805941872748998094254742173582401063677404595741785160829230135358081840096996372524230560855903700624271243416909004153690105933983835777939410970027753472000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000L

从版本10.4.8开始,newLISP内置了对无限精度整数的bigint支持

bigint递归阶乘:

> (define (fac n) (if (= n 1) 1 (* (bigint n) (fac (- n 1)))))
> (fac 20)
2432902008176640000L
> (fac 30)
265252859812191058636308480000000L
> (fac 40)
815915283247897734345611269596115894272000000000L

fac 100=>9.332621544e+157,太棒了!然而,newlisp无法计算fac 1000,但ECL可以!顺便说一句,为什么+-*/不像CL那样是多态的?手册告诉您如何定义这些运算符,以便它们处理不精确的FP数以及精确的整数…:
> (define (fac n) (if (= n 1) 1 (* (bigint n) (fac (- n 1)))))
> (fac 20)
2432902008176640000L
> (fac 30)
265252859812191058636308480000000L
> (fac 40)
815915283247897734345611269596115894272000000000L