Elixir 更高级:与长生不老药苦艾酒协会
我的博客应用程序有一个Elixir 更高级:与长生不老药苦艾酒协会,elixir,graphql,ecto,absinthe,Elixir,Graphql,Ecto,Absinthe,我的博客应用程序有一个Post模型,其中有许多评论 schema "post" do field :title, :string field :content, :string belongs_to :owner, MyApp.Accounts.User, foreign_key: :owner_id has_many :comments, MyApp.Content.Comment, foreign_key: :post_id timestamps() end 我也
Post
模型,其中有许多评论
schema "post" do
field :title, :string
field :content, :string
belongs_to :owner, MyApp.Accounts.User, foreign_key: :owner_id
has_many :comments, MyApp.Content.Comment, foreign_key: :post_id
timestamps()
end
我也有一个相关的苦艾酒对象
object :post do
field :id, :integer
field :title, :string
field :content, :string
field :owner, :user, resolve: assoc(:owner)
field :comments, list_of(:comment), resolve: assoc(:comments)
end
查询按预期工作
现在我想在注释
模式中添加一个布尔活动
字段,以便执行软删除;我将只选择active==true
的注释,并通过将active
设置为false
来删除注释
我将字段添加到我的架构中:
field :active, :boolean, default: true, null: false
现在,我只希望苦艾酒:comments
字段返回活动注释。我有一个自定义的解析程序
field :comments, list_of(:comment), resolve: fn (query,_,resolution) ->
query =
from c in MyApp.Content.Comment,
where: c.post_id == ^query.id,
where: c.active == true,
select: c
{:ok, MyApp.Repo.all(query)}
end
我担心这会遇到N+1问题。有更优雅的方法吗?您需要在此处使用批处理解析器。报告详细解释了一切。您的查询应如下所示:
query =
from c in MyApp.Content.Comment,
where: c.post_id in ^post_ids,
where: c.active == true,
select: c
{:ok, query |> MyApp.Repo.all() |> Enum.group_by(& &1.post_id)}
您需要在此处使用批处理解析器。报告详细解释了一切。您的查询应如下所示:
query =
from c in MyApp.Content.Comment,
where: c.post_id in ^post_ids,
where: c.active == true,
select: c
{:ok, query |> MyApp.Repo.all() |> Enum.group_by(& &1.post_id)}