如何使用VB脚本对excel工作表中的行进行排序并打印到文件中?
我有一张名为student的桌子。我正试图打印出与他的分数相对应的学生姓名。我想使用Excel宏打印到文件 我的表格包含标题,如学生姓名1、2、3等。。相应的标记为1、2、3、4和“-” 我想在VB中编写函数,将对应的行按每个主题(0,1,2,3,…7)排序,并将值打印到文件中 输出(file.txt) 行中的列应按升序排序,如果任何列中出现“-”,则应将其打印为空值作为剩余值 我写过如何使用VB脚本对excel工作表中的行进行排序并打印到文件中?,excel,vba,Excel,Vba,我有一张名为student的桌子。我正试图打印出与他的分数相对应的学生姓名。我想使用Excel宏打印到文件 我的表格包含标题,如学生姓名1、2、3等。。相应的标记为1、2、3、4和“-” 我想在VB中编写函数,将对应的行按每个主题(0,1,2,3,…7)排序,并将值打印到文件中 输出(file.txt) 行中的列应按升序排序,如果任何列中出现“-”,则应将其打印为空值作为剩余值 我写过 Sub test() 'create and write into file txt Dim fso As
Sub test()
'create and write into file txt
Dim fso As Object
Set fso = CreateObject("Scripting.FileSystemObject")
Dim Fileout As Object
Set Fileout = fso.CreateTextFile("MyFile.txt", True, True)
'Write logic for sorting
Fileout.Close
End Sub
如何使用VB脚本在excel中排序并打印这些行 以下是一种实现方法,根据您的需要调整它:
' Naive O(N^2) sort
Sub Sort(arr() As Long, students() As String)
If UBound(arr) <= 1 Then Exit Sub
Dim i As Long, j As Long
For i = 0 To UBound(arr) - 1
' Look for the minimum index in the sub-array going from i
Dim indexOfMin As Long
indexOfMin = i
For j = i To UBound(arr)
If arr(j) < arr(indexOfMin) Then
indexOfMin = j
End If
Next j
' Put the minimum mark at the beginning of the sub-array
Dim tmp As Variant
tmp = arr(i)
arr(i) = arr(indexOfMin)
arr(indexOfMin) = tmp
' Put the student with the minimum value at the beginning of the students sub-array
tmp = students(i)
students(i) = students(indexOfMin)
students(indexOfMin) = tmp
Next i
End Sub
Sub SortAndSave()
Dim dataRange As Range
Set dataRange = Range("A1:F9")
Dim data As Variant
data = dataRange.Value
Dim NSubject As Long, NStudents As Long
NSubject = UBound(data, 1) - 1
NStudents = UBound(data, 2) - 1
Dim text As String
Dim i As Long, j As Long
For i = 1 To NSubject
' Read marks and students names
Dim subjectMarks() As Long
ReDim subjectMarks(0 To NStudents - 1)
Dim students() As String
ReDim students(0 To NStudents - 1)
For j = 1 To NStudents
' Use a big enough number 999 so that students with no mark will be pushed to the end
subjectMarks(j - 1) = IIf(data(i + 1, j + 1) <> "-", data(i + 1, j + 1), 999)
students(j - 1) = data(1, j + 1)
Next j
' Sort marks and students
Sort subjectMarks, students
' Build display row for subject
Dim row As String
row = ""
For j = 1 To NStudents
' If there is a mark render the student name
If subjectMarks(j - 1) <> 999 Then
row = row & students(j - 1)
' Otherwise render NULL
Else
row = row & "NULL"
End If
' Add a comma if not the latest
If j <> NStudents Then
row = row & ","
End If
Next j
text = text & row
' Add a \r\n if not the latest
If i <> NSubject Then
text = text & vbCrLf
End If
Next i
End Sub
您想要VBScript还是VBA?它们与Excel的VB脚本不同,因为你提到了Excel宏,你的示例代码是VBA,我假设你指的是VBA,而不是VBScript。如果不是这样的话,您可以将其还原。此答案使用VBA,而不是VBScript。事实上,我得出了与您相同的结论:OP需要VBA。:)否则他会告诉我们…我想要VBA。谢谢你宝贵的帮助support@Pragmateek运行时,在行subjectMarks(j-1)=IIf(数据(i+1,j+1)“-”,数据(i+1,j+1),999)中获取“类型不匹配错误”script@user2986042您的数据范围中可能有错误的值,即既不是
-
也不是整数。
' Naive O(N^2) sort
Sub Sort(arr() As Long, students() As String)
If UBound(arr) <= 1 Then Exit Sub
Dim i As Long, j As Long
For i = 0 To UBound(arr) - 1
' Look for the minimum index in the sub-array going from i
Dim indexOfMin As Long
indexOfMin = i
For j = i To UBound(arr)
If arr(j) < arr(indexOfMin) Then
indexOfMin = j
End If
Next j
' Put the minimum mark at the beginning of the sub-array
Dim tmp As Variant
tmp = arr(i)
arr(i) = arr(indexOfMin)
arr(indexOfMin) = tmp
' Put the student with the minimum value at the beginning of the students sub-array
tmp = students(i)
students(i) = students(indexOfMin)
students(indexOfMin) = tmp
Next i
End Sub
Sub SortAndSave()
Dim dataRange As Range
Set dataRange = Range("A1:F9")
Dim data As Variant
data = dataRange.Value
Dim NSubject As Long, NStudents As Long
NSubject = UBound(data, 1) - 1
NStudents = UBound(data, 2) - 1
Dim text As String
Dim i As Long, j As Long
For i = 1 To NSubject
' Read marks and students names
Dim subjectMarks() As Long
ReDim subjectMarks(0 To NStudents - 1)
Dim students() As String
ReDim students(0 To NStudents - 1)
For j = 1 To NStudents
' Use a big enough number 999 so that students with no mark will be pushed to the end
subjectMarks(j - 1) = IIf(data(i + 1, j + 1) <> "-", data(i + 1, j + 1), 999)
students(j - 1) = data(1, j + 1)
Next j
' Sort marks and students
Sort subjectMarks, students
' Build display row for subject
Dim row As String
row = ""
For j = 1 To NStudents
' If there is a mark render the student name
If subjectMarks(j - 1) <> 999 Then
row = row & students(j - 1)
' Otherwise render NULL
Else
row = row & "NULL"
End If
' Add a comma if not the latest
If j <> NStudents Then
row = row & ","
End If
Next j
text = text & row
' Add a \r\n if not the latest
If i <> NSubject Then
text = text & vbCrLf
End If
Next i
End Sub
NULL,NULL,NULL,NULL,NULL
STUDENT 2,STUDENT 5,STUDENT 4,NULL,NULL
STUDENT 4,STUDENT 5,NULL,NULL,NULL
STUDENT 4,STUDENT 5,NULL,NULL,NULL
STUDENT 2,STUDENT 5,STUDENT 4,NULL,NULL
STUDENT 5,STUDENT 4,STUDENT 2,STUDENT 1,NULL
STUDENT 5,STUDENT 4,STUDENT 2,STUDENT 1,NULL
STUDENT 4,STUDENT 5,NULL,NULL,NULL