Flask Request.400烧瓶中的错误请求

在我的项目中有一个项目，我正在上传一个我正在开发的应用程序。我有2个图像上传区域。我加载2时没有任何问题。400错误请求：KeyError：当我上传图像时，或当我从未加载图像时按下发送按钮时，我在“gelinFoto”样式中遇到错误。我哪里出错了

def admin():
form = KisiForm(request.form)
    if request.method == "POST":
        gelinFoto = request.files['gelinFoto']
        damatFoto = request.files['damatFoto']

        if gelinFoto or damatFoto:
            yol = app.config['UPLOAD_FOLDER'] + whuser
            yol = yol + '/profil'
            gfilename = secure_filename(gelinFoto.filename)
            dfilename = secure_filename(damatFoto.filename)
            gelinFoto.save(os.path.join(yol, gfilename))
            damatFoto.save(os.path.join(yol, dfilename))

        kisi = bilgi(gelinFoto = gfilename, damatFoto = dfilename)
        db.session.add(kisi)
        db.session.commit()
        return redirect(url_for("admin"))
    return render_template("admin/index.html",form=form)

Html

格里宁·福托拉夫：
{{render_字段（form.gelinfo，id=“gelinfo”，class=“gdfoto”，accept=“.png，.jpg，.jpeg”）}
格列宁·福托拉夫·恩努伊伊尼茨（Gelinin fotoğrafınıyükleyiniz）。
Damatın Fotoğrafı
{{render_字段（form.damatFoto，id=“damatFoto”，class=“gdfoto”，accept=“.png，.jpg，.jpeg”）}
Damatın fotoğrafınıyükleyiniz。

---

在你看来，两者都有

gelinFoto = request.files['gelinFoto']
damatFoto = request.files['damatFoto']

这就是为什么你会犯这个错误

如果没有提供该文件，那么就没有

请求。例如，files['gelinfo']

，Python会尝试查找它，但这不会导致没有名为

gelinfo

的键

最简单的技巧是定义如下主题：

gelinFoto = request.files.get('gelinFoto', None)
damatFoto = request.files.get('damatFoto', None)

通过这种方式，它使用一个内联条件来获取密钥，如果没有提供密钥，则设置值

None

后来在你的代码里我看到你又这么做了

if gelinFoto or damatFoto:
    # ... Your other coders 
    gfilename = secure_filename(gelinFoto.filename)
    dfilename = secure_filename(damatFoto.filename)
    gelinFoto.save(os.path.join(yol, gfilename))
    damatFoto.save(os.path.join(yol, dfilename))

这是错误的，您正在用

或
检查它，然后用u检查，除非两者都不是
None

最好对每一个单独进行操作，如：

if gelinFoto:
    yol = app.config['UPLOAD_FOLDER'] + whuser
    yol = yol + '/profil'
    gfilename = secure_filename(gelinFoto.filename)
    gelinFoto.save(os.path.join(yol, gfilename)

if damatFoto:
    yol = app.config['UPLOAD_FOLDER'] + whuser
    yol = yol + '/profil'
    dfilename = secure_filename(damatFoto.filename)
    damatFoto.save(os.path.join(yol, dfilename)

# I'm not sure if there is a better way to do this but about kisi line This is the best that came up to me ( ofcourse there are better ways )
if gelinFoto and damatFoto:
    kisi = bilgi(gelinFoto = gfilename, damatFoto = dfilename)
elif gelinFoto:
    kisi = bilgi(gelinFoto = gfilename)
elif damatFoto:
    kisi = bilgi(damatFoto = dfilename)

不幸的是，这个问题没有改变。我也犯了同样的错误。@berabozkurt提供了更多信息，比如整个回溯message@BeratBozkurt将这些数据作为文本/代码添加到您的问题中，顺便说一句，您没有更改我说的内容，您希望错误如何消失？@berabozkurt抱歉，这是一个小错误，更新了答案，
request.get
更改为
request.files.get
，这应该可以正常工作。还有一个错误：）我在if dfilename和gfilename中的赋值错误之前引用了一个局部变量“dfilename”：
if gelinFoto:
    yol = app.config['UPLOAD_FOLDER'] + whuser
    yol = yol + '/profil'
    gfilename = secure_filename(gelinFoto.filename)
    gelinFoto.save(os.path.join(yol, gfilename)

if damatFoto:
    yol = app.config['UPLOAD_FOLDER'] + whuser
    yol = yol + '/profil'
    dfilename = secure_filename(damatFoto.filename)
    damatFoto.save(os.path.join(yol, dfilename)

# I'm not sure if there is a better way to do this but about kisi line This is the best that came up to me ( ofcourse there are better ways )
if gelinFoto and damatFoto:
    kisi = bilgi(gelinFoto = gfilename, damatFoto = dfilename)
elif gelinFoto:
    kisi = bilgi(gelinFoto = gfilename)
elif damatFoto:
    kisi = bilgi(damatFoto = dfilename)