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Flutter 如何从Flatter中的sqlite获取最后一个条目?_Flutter_Sqflite - Fatal编程技术网

Flutter 如何从Flatter中的sqlite获取最后一个条目?

Flutter 如何从Flatter中的sqlite获取最后一个条目?,flutter,sqflite,Flutter,Sqflite,我在SO中看到了很多答案,但都与android有关 我想获取表中输入的最后一个ID。这是我的用户表: await db.execute("CREATE TABLE User(" "userId INTEGER PRIMARY KEY," "first_name TEXT," "last_name TEXT," "user_password TEXT," "mobile_no TEXT,"

我在SO中看到了很多答案,但都与android有关

我想获取表中输入的最后一个ID。这是我的用户表:

await db.execute("CREATE TABLE User("
          "userId INTEGER PRIMARY KEY,"
          "first_name TEXT,"
          "last_name TEXT,"
          "user_password TEXT,"
          "mobile_no TEXT,"
          "email_id TEXT," 
          ")");
    print("User Table created");
您可以使用Order by和Limit关键字。我现在不能自己测试,但谷歌说他们在sqflite上受支持。应该是这样的:

db.rawQuery("SELECT * FROM $table ORDER BY userId DESC LIMIT 1");
 db.query(
      dbTable, 
      orderBy: "userId DESC",
      limit: 1
    );
或者像这样:

db.rawQuery("SELECT * FROM $table ORDER BY userId DESC LIMIT 1");
 db.query(
      dbTable, 
      orderBy: "userId DESC",
      limit: 1
    );
您可以使用Order by和Limit关键字。我现在不能自己测试,但谷歌说他们在sqflite上受支持。应该是这样的:

db.rawQuery("SELECT * FROM $table ORDER BY userId DESC LIMIT 1");
 db.query(
      dbTable, 
      orderBy: "userId DESC",
      limit: 1
    );
或者像这样:

db.rawQuery("SELECT * FROM $table ORDER BY userId DESC LIMIT 1");
 db.query(
      dbTable, 
      orderBy: "userId DESC",
      limit: 1
    );