Beego/Golang-向结构查询值
我有一个使用Beego框架在Golang中构建的API,我有一个具有多个连接的查询,然后返回一个JSON结果 我希望有一种方法可以将每一行转换成一个具有更好的键名的结构,例如,而不是“Stage\uu Description”只是“Stage”,等等。。。所以我用我想要的键名构建了一个ResultMap结构,我应该创建一个映射吗 查询:Beego/Golang-向结构查询值,go,beego,Go,Beego,我有一个使用Beego框架在Golang中构建的API,我有一个具有多个连接的查询,然后返回一个JSON结果 我希望有一种方法可以将每一行转换成一个具有更好的键名的结构,例如,而不是“Stage\uu Description”只是“Stage”,等等。。。所以我用我想要的键名构建了一个ResultMap结构,我应该创建一个映射吗 查询: type ResultMap struct { Id int DateAdded time.Time FirstName
type ResultMap struct {
Id int
DateAdded time.Time
FirstName string
LastName string
Username string
Stage string
station string
status string
}
//var maps []ResultMap
var maps []orm.Params
num, err := o.QueryTable("test_result_detail").
Filter("Result__Serial", "121994-0001").
Values(&maps, "id", "date_added", "stage__description", "station__station", "status__status", "operator__username", "operator__first_name", "operator__last_name" )
JSON结果
[
{
"DateAdded": "2016-10-20T00:00:00-05:00",
"Id": 8306105,
"Operator__FirstName": "Jose",
"Operator__LastName": "Mendez",
"Operator__Username": "3362",
"Stage__Description": "VR1 Test",
"Station__Station": "TS0653",
"Status__Status": "PASS"
},
{
"DateAdded": "2016-10-20T00:00:00-05:00",
"Id": 8306465,
"Operator__FirstName": "Jose",
"Operator__LastName": "Mendez",
"Operator__Username": "3362",
"Stage__Description": "QA Lab X-Ray Inspection",
"Station__Station": "LABEQP-0004",
"Status__Status": "PASS"
},
{
"DateAdded": "2016-10-28T00:00:00-05:00",
"Id": 8547267,
"Operator__FirstName": "Jose",
"Operator__LastName": "Mendez",
"Operator__Username": "3362",
"Stage__Description": "Capture Customer SN",
"Station__Station": "N/A",
"Status__Status": "PASS"
},
{
"DateAdded": "2016-10-28T00:00:00-05:00",
"Id": 8547851,
"Operator__FirstName": "Jose",
"Operator__LastName": "Mendez",
"Operator__Username": "3362",
"Stage__Description": "Final Test",
"Station__Station": "TS0653",
"Status__Status": "PASS"
},
{
"DateAdded": "2017-02-14T00:00:00-06:00",
"Id": 10993864,
"Operator__FirstName": "Jose",
"Operator__LastName": "Mendez",
"Operator__Username": "3362",
"Stage__Description": "QA Mechanical Final Inspection",
"Station__Station": "VISUAL INSPECTION",
"Status__Status": "PASS"
}
]
您希望在结构上使用json注释,然后使用
json.Unmarshal
将数据放入结构中
以下是一个例子:
package main
import (
"encoding/json"
"fmt"
)
func main() {
// The struct you want to store the data in
// Note the json tags that show which json field corresponds to which struct field
type Data struct {
FirstName string `json:"Operator__FirstName"`
LastName string `json:"Operator__LastName"`
}
// Create a slice of these structs since our json is an array of results
var structData []Data
// The json you want to dump into the structs
jsonData := []byte(`[{"Operator__FirstName": "Bob", "Operator__LastName": "Smith"},{"Operator__FirstName": "John", "Operator__LastName": "Adams"}]`)
_ = json.Unmarshal(jsonData, &structData)
fmt.Printf("%+v", structData)
}
这里是Go Playerd:你能告诉我如何在上面的maps对象上迭代多个结果吗?我更新了上面的示例,以处理一个具有多个结果的json数组。基本上,您只需要创建一个结构切片,然后将其解组。