Google bigquery 如何将毫秒与日期添加和日期差异一起使用

我尝试在bigquery中使用带日期的毫秒添加函数时遇到了一些困难：

我正在尝试这个SQL，它对我不起作用

DATE_ADD(MILLISECOND,-1,LEAD(dt) OVER (PARTITION BY xy ORDER BY dt ASC)

还正在寻找

DATE\u DIFF

函数的解决方案

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非常感谢您的帮助。

这是一个使用

DATETIME\u ADD

SELECT *, DATETIME_DIFF(seq_date,LEAD_DT, HOUR) FROM  
(SELECT *, RANK() OVER (PARTITION BY ID ORDER BY seq_date) AS RNK,
DATETIME_ADD((LEAD(seq_date) OVER (PARTITION BY ID ORDER BY seq_date)) ,INTERVAL 3 HOUR) LEAD_DT
FROM 
(select 1 as id, CURRENT_DATETIME() as seq_date, 10 as cost
union ALL
select 1 as id, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL -10 MINUTE ) as seq_date, 12 as cost
UNION ALL
select 1 as id, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL -1 HOUR ) as seq_date, 13 as cost
UNION ALL
select 1 as id, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL 5 HOUR ) as seq_date, 20 as cost));

SELECT *, DATE_DIFF(seq_date,LEAD_DT, DAY) FROM  
(SELECT *, RANK() OVER (PARTITION BY ID ORDER BY seq_date) AS RNK,
DATE_ADD((LEAD(seq_date) OVER (PARTITION BY ID ORDER BY seq_date)) ,INTERVAL 3 DAY) LEAD_DT
FROM 
(select 1 as id, CURRENT_DATE() as seq_date, 10 as cost
union ALL
select 1 as id, DATE_ADD(CURRENT_DATE(), INTERVAL -10 DAY ) as seq_date, 12 as cost
UNION ALL
select 1 as id, DATE_ADD(CURRENT_DATE(), INTERVAL -1 DAY ) as seq_date, 13 as cost
UNION ALL
select 1 as id, DATE_ADD(CURRENT_DATE(), INTERVAL 5 DAY ) as seq_date, 20 as cost));

---

这是一个使用

DATE\u ADD

SELECT *, DATETIME_DIFF(seq_date,LEAD_DT, HOUR) FROM  
(SELECT *, RANK() OVER (PARTITION BY ID ORDER BY seq_date) AS RNK,
DATETIME_ADD((LEAD(seq_date) OVER (PARTITION BY ID ORDER BY seq_date)) ,INTERVAL 3 HOUR) LEAD_DT
FROM 
(select 1 as id, CURRENT_DATETIME() as seq_date, 10 as cost
union ALL
select 1 as id, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL -10 MINUTE ) as seq_date, 12 as cost
UNION ALL
select 1 as id, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL -1 HOUR ) as seq_date, 13 as cost
UNION ALL
select 1 as id, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL 5 HOUR ) as seq_date, 20 as cost));

SELECT *, DATE_DIFF(seq_date,LEAD_DT, DAY) FROM  
(SELECT *, RANK() OVER (PARTITION BY ID ORDER BY seq_date) AS RNK,
DATE_ADD((LEAD(seq_date) OVER (PARTITION BY ID ORDER BY seq_date)) ,INTERVAL 3 DAY) LEAD_DT
FROM 
(select 1 as id, CURRENT_DATE() as seq_date, 10 as cost
union ALL
select 1 as id, DATE_ADD(CURRENT_DATE(), INTERVAL -10 DAY ) as seq_date, 12 as cost
UNION ALL
select 1 as id, DATE_ADD(CURRENT_DATE(), INTERVAL -1 DAY ) as seq_date, 13 as cost
UNION ALL
select 1 as id, DATE_ADD(CURRENT_DATE(), INTERVAL 5 DAY ) as seq_date, 20 as cost));

---

有关更多详细信息，请参见下文

这是一个使用

DATETIME\u ADD

SELECT *, DATETIME_DIFF(seq_date,LEAD_DT, HOUR) FROM  
(SELECT *, RANK() OVER (PARTITION BY ID ORDER BY seq_date) AS RNK,
DATETIME_ADD((LEAD(seq_date) OVER (PARTITION BY ID ORDER BY seq_date)) ,INTERVAL 3 HOUR) LEAD_DT
FROM 
(select 1 as id, CURRENT_DATETIME() as seq_date, 10 as cost
union ALL
select 1 as id, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL -10 MINUTE ) as seq_date, 12 as cost
UNION ALL
select 1 as id, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL -1 HOUR ) as seq_date, 13 as cost
UNION ALL
select 1 as id, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL 5 HOUR ) as seq_date, 20 as cost));

SELECT *, DATE_DIFF(seq_date,LEAD_DT, DAY) FROM  
(SELECT *, RANK() OVER (PARTITION BY ID ORDER BY seq_date) AS RNK,
DATE_ADD((LEAD(seq_date) OVER (PARTITION BY ID ORDER BY seq_date)) ,INTERVAL 3 DAY) LEAD_DT
FROM 
(select 1 as id, CURRENT_DATE() as seq_date, 10 as cost
union ALL
select 1 as id, DATE_ADD(CURRENT_DATE(), INTERVAL -10 DAY ) as seq_date, 12 as cost
UNION ALL
select 1 as id, DATE_ADD(CURRENT_DATE(), INTERVAL -1 DAY ) as seq_date, 13 as cost
UNION ALL
select 1 as id, DATE_ADD(CURRENT_DATE(), INTERVAL 5 DAY ) as seq_date, 20 as cost));

---

这是一个使用

DATE\u ADD

SELECT *, DATETIME_DIFF(seq_date,LEAD_DT, HOUR) FROM  
(SELECT *, RANK() OVER (PARTITION BY ID ORDER BY seq_date) AS RNK,
DATETIME_ADD((LEAD(seq_date) OVER (PARTITION BY ID ORDER BY seq_date)) ,INTERVAL 3 HOUR) LEAD_DT
FROM 
(select 1 as id, CURRENT_DATETIME() as seq_date, 10 as cost
union ALL
select 1 as id, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL -10 MINUTE ) as seq_date, 12 as cost
UNION ALL
select 1 as id, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL -1 HOUR ) as seq_date, 13 as cost
UNION ALL
select 1 as id, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL 5 HOUR ) as seq_date, 20 as cost));

SELECT *, DATE_DIFF(seq_date,LEAD_DT, DAY) FROM  
(SELECT *, RANK() OVER (PARTITION BY ID ORDER BY seq_date) AS RNK,
DATE_ADD((LEAD(seq_date) OVER (PARTITION BY ID ORDER BY seq_date)) ,INTERVAL 3 DAY) LEAD_DT
FROM 
(select 1 as id, CURRENT_DATE() as seq_date, 10 as cost
union ALL
select 1 as id, DATE_ADD(CURRENT_DATE(), INTERVAL -10 DAY ) as seq_date, 12 as cost
UNION ALL
select 1 as id, DATE_ADD(CURRENT_DATE(), INTERVAL -1 DAY ) as seq_date, 13 as cost
UNION ALL
select 1 as id, DATE_ADD(CURRENT_DATE(), INTERVAL 5 DAY ) as seq_date, 20 as cost));

有关更多详细信息，请参见下文

需要日期部分作为参数。你可以用这个。这对我有用：

DATETIME_ADD(LEAD(validfrom) OVER (PARTITION BY xy ORDER BY validfrom ASC), INTERVAL -1 MILLISECOND) as validto

玩一些虚拟数据：

WITH test_table as
(
    SELECT 1 AS xy, CURRENT_DATETIME() AS validfrom UNION ALL
    SELECT 1 AS xy, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL 1 MINUTE ) AS validfrom UNION ALL
    SELECT 1 AS xy, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL 2 MINUTE ) AS validfrom UNION ALL
    SELECT 1 AS xy, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL 3 MINUTE ) AS validfrom
)
SELECT
  *,
  DATETIME_ADD(LEAD(validfrom) OVER (PARTITION BY xy ORDER BY validfrom ASC), INTERVAL -1 MILLISECOND) as validto
FROM test_table;

结果是：

Row xy  validfrom                   validto  
1   1   2019-03-18T15:06:18.086840  2019-03-18T15:07:18.085840   
2   1   2019-03-18T15:07:18.086840  2019-03-18T15:08:18.085840   
3   1   2019-03-18T15:08:18.086840  2019-03-18T15:09:18.085840   
4   1   2019-03-18T15:09:18.086840  null    

请注意，

validto

字段比下一行的

validfrom

早1毫秒，这应该是预期结果。

需要日期部分作为参数。你可以用这个。这对我有用：

DATETIME_ADD(LEAD(validfrom) OVER (PARTITION BY xy ORDER BY validfrom ASC), INTERVAL -1 MILLISECOND) as validto

玩一些虚拟数据：

WITH test_table as
(
    SELECT 1 AS xy, CURRENT_DATETIME() AS validfrom UNION ALL
    SELECT 1 AS xy, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL 1 MINUTE ) AS validfrom UNION ALL
    SELECT 1 AS xy, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL 2 MINUTE ) AS validfrom UNION ALL
    SELECT 1 AS xy, DATETIME_ADD(CURRENT_DATETIME(), INTERVAL 3 MINUTE ) AS validfrom
)
SELECT
  *,
  DATETIME_ADD(LEAD(validfrom) OVER (PARTITION BY xy ORDER BY validfrom ASC), INTERVAL -1 MILLISECOND) as validto
FROM test_table;

结果是：

Row xy  validfrom                   validto  
1   1   2019-03-18T15:06:18.086840  2019-03-18T15:07:18.085840   
2   1   2019-03-18T15:07:18.086840  2019-03-18T15:08:18.085840   
3   1   2019-03-18T15:08:18.086840  2019-03-18T15:09:18.085840   
4   1   2019-03-18T15:09:18.086840  null    

---

请注意，

validto

字段比下一行的

validfrom

早1毫秒，这应该是预期的结果。

您能说明此查询的目标是什么吗？样本数据？想要的结果？对不起，没有早点说清楚。我试图找到dt（validfrom）字段的前导值和毫秒数的-1，并将其作为validto加载到一个新的dt字段。当我在上面的部分中使用毫秒时，我得到了一个错误。我想知道在DATE\u ADD函数中，SQL毫秒和BQ毫秒的等效值是多少。你能说明一下这个查询的目的是什么吗？样本数据？想要的结果？对不起，没有早点说清楚。我试图找到dt（validfrom）字段的前导值和毫秒数的-1，并将其作为validto加载到一个新的dt字段。当我在上面的部分中使用毫秒时，我得到了一个错误。我试图弄清楚在DATE\u ADD函数中，SQL毫秒与BQ毫秒的等效值是什么。