Grails 瑞穗星级问题

我正在为Grails开发一个带有RichUI插件的评级系统。首先，我有以下代码：

class RatingController {

def springSecurityService

static scaffold = true

def rate = {
    def rating = params.rating
    def artist = Artist.get( params.id )
    def currentUser = currentUser()

    currentUser.addToRatings(new Rating(artist:artist, rating:rating)).save()
    render(template: "/artist/rate", model: [artist: artist, rating: rating])

    }

private currentUser(){
    return User.get(springSecurityService.principal.id)
}
}

class RatingController {

def springSecurityService

static scaffold = true

def rate = {
    def rating = params.rating
    def artist = Artist.get( params.id )
    def currentUser = currentUser()

    if(! currentUser.ratings.artist.contains(artist)){
        currentUser.addToRatings(new Rating(artist:artist, rating:rating)).save()
        render(template: "/artist/rate", model: [artist: artist, rating: rating])
    }

    else{
        currentUser.ratings.find{it.artist==artist}.rating = rating
        currentUser.save()
        render(template: "/artist/rate", model: [artist: artist, rating: rating])
    }
}

private currentUser(){
    return User.get(springSecurityService.principal.id)
}
}

这很好，但是这段代码的问题是，如果用户更新某个艺术家的评级，它总是会创建一个新的评级实例，而不仅仅是更新评级值。 所以我想出了以下代码：

class RatingController {

def springSecurityService

static scaffold = true

def rate = {
    def rating = params.rating
    def artist = Artist.get( params.id )
    def currentUser = currentUser()

    currentUser.addToRatings(new Rating(artist:artist, rating:rating)).save()
    render(template: "/artist/rate", model: [artist: artist, rating: rating])

    }

private currentUser(){
    return User.get(springSecurityService.principal.id)
}
}

class RatingController {

def springSecurityService

static scaffold = true

def rate = {
    def rating = params.rating
    def artist = Artist.get( params.id )
    def currentUser = currentUser()

    if(! currentUser.ratings.artist.contains(artist)){
        currentUser.addToRatings(new Rating(artist:artist, rating:rating)).save()
        render(template: "/artist/rate", model: [artist: artist, rating: rating])
    }

    else{
        currentUser.ratings.find{it.artist==artist}.rating = rating
        currentUser.save()
        render(template: "/artist/rate", model: [artist: artist, rating: rating])
    }
}

private currentUser(){
    return User.get(springSecurityService.principal.id)
}
}

但使用此代码，当评级值被分配给“else”块中的新评级（params.rating）时，它被分配给50左右的随机数（如53）。我看不出问题出在哪里。 如果你能帮我一点忙，我将不胜感激。

---

非常感谢。

我刚找到问题所在。我必须将评级的输入值转换为double类型。因此，以下代码按预期工作：

class RatingController {

    def springSecurityService

    static scaffold = true

    def rate = {
        def rating = params.rating.toDouble()
        def artist = Artist.get( params.id )
        def currentUser = currentUser()

        if(! currentUser.ratings.artist.contains(artist)){
           currentUser.addToRatings(new Rating(artist:artist, rating:rating)).save()
           render(template: "/artist/rate", model: [artist: artist, rating: rating])
        }

        else{
           currentUser.ratings.find{it.artist==artist}.rating = rating
           currentUser.save()
           render(template: "/artist/rate", model: [artist: artist, rating: rating])
        }
   }

   private currentUser(){
        return User.get(springSecurityService.principal.id)
   }
   }

FWIW，一种“groovier”的方法是

def rating=params.rating as Double

-没有太大区别，但如果您有兴趣了解其他语法，则可以使用不同的选项。：）