如何在haskell中合并两个列表

我有两个列表

x=[“a”、“b”、“c”]

和

y=[“阿根廷”、“巴西”、“加拿大”]

。我想要一个列表，像

[[“a”，“阿根廷”]，[“b”，“巴西”]，[“c”，“加拿大”]

。

---

有人能帮我吗？谢谢。

我不确定是否有更简单的方法，但您可以使用

zip

生成元组列表，然后

将其映射回列表中

Prelude> map (\(a,b) -> [a,b]) $ zip ["a","b","c"] ["Argentina","Brazil","Canada"]
[["a","Argentina"],["b","Brazil"],["c","Canada"]]

Edit：丹尼尔·马丁指出
zipWith
更简单

Prelude> zipWith (\a b -> [a,b]) ["a","b","c"] ["Argentina","Brazil","Canada"]
[["a","Argentina"],["b","Brazil"],["c","Canada"]]

我不确定是否有更简单的方法，但您可以使用
zip
生成元组列表，然后
将其映射回列表中

Prelude> map (\(a,b) -> [a,b]) $ zip ["a","b","c"] ["Argentina","Brazil","Canada"]
[["a","Argentina"],["b","Brazil"],["c","Canada"]]

Edit：丹尼尔·马丁指出
zipWith
更简单

Prelude> zipWith (\a b -> [a,b]) ["a","b","c"] ["Argentina","Brazil","Canada"]
[["a","Argentina"],["b","Brazil"],["c","Canada"]]

简单使用

zipWith (\x y -> [x,y])

简单使用

zipWith (\x y -> [x,y])

在没有看到您的用例的情况下，我猜元组实际上已经足够了，并且更安全，因此这只是
zip

x = ["a","b","c"]
y = ["Argentina","Brazil","Canada"]
z = zip x y

Prelude> z
[("a","Argentina"),("b","Brazil"),("c","Canada")]

在没有看到您的用例的情况下，我猜元组实际上已经足够了，并且更安全，因此这只是
zip

x = ["a","b","c"]
y = ["Argentina","Brazil","Canada"]
z = zip x y

Prelude> z
[("a","Argentina"),("b","Brazil"),("c","Canada")]

或者跳过
map
只使用
zipWith
。或者跳过
map
只使用
zipWith
。看起来像课程作业。看起来像课程作业。