hive:加入regex
我想用regex/rlike条件实现一个连接。但蜂巢不起作用hive:加入regex,hive,Hive,我想用regex/rlike条件实现一个连接。但蜂巢不起作用 select a.col_1, b.col_2 from table1 a left join table2 b on a.col_1 rlike b.col_2 这实际上是可行的,但我想将b.col2中的全文与a.colu_1中的字符串相匹配。有办法做到这一点吗 示例数据集: **table1** apple iphone apple iphone 6s google nexus samsung galaxy tab **t
select a.col_1, b.col_2
from table1 a left join table2 b
on a.col_1 rlike b.col_2
这实际上是可行的,但我想将b.col2中的全文与a.colu_1中的字符串相匹配。有办法做到这一点吗
示例数据集:
**table1**
apple iphone
apple iphone 6s
google nexus
samsung galaxy tab
**table2**
apple
google
nexus
**outcome**
col1 col2
apple iphone apple
apple iphone 6s apple
google nexus google
samsung galaxy tab null
是否有任何逻辑可用于使用字符串操作隔离
col1
中感兴趣的字符串?一些示例数据在这里会很有帮助。不幸的是,没有。我正在处理搜索关键字。因此,我想将表2中的“苹果”品牌与表1中的关键词“苹果iphone 6s”进行匹配。换句话说,我想找出表2[全文]中有多少关键字与表1中的关键字相匹配。@TimBiegeleisen添加了示例数据集搜索关键字是否总是单个单词?表1是否有ID列?
select col1
,col2
from (select t1.col1
,t2.col2
,count (col2) over (partition by col1) as count_col2
,row_number () over (partition by col1,col2) as rn
from (select *
from table1 t1
lateral view explode(split(col1,'\\s+')) e as token
) t1
left join (select *
from table2 t2
lateral view explode(split(col2,'\\s+')) e as token
) t2
on t2.token =
t1.token
) t
where ( count_col2 = 0
or col1 rlike concat ('\\b',col2,'\\b')
)
and rn = 1
;
+--------------------+--------+
| col1 | col2 |
+--------------------+--------+
| apple iphone | apple |
| apple iphone 6s | apple |
| google nexus | google |
| google nexus | nexus |
| samsung galaxy tab | (null) |
+--------------------+--------+