Image 文件\u get\u contents（）要求参数1为有效路径

我的图像已成功上载到图像/新闻。现在我想将该图像保存到数据库中。但它总是给我上述的错误。我的模型查询是正确的，因为我使用它来插入其他数据，它可以工作

用户单击提交后，如何将图像保存到数据库中

我的控制器：

 function news()
{

 $config = array(
'upload_path' => "./images/news",
'allowed_types' => "gif|jpg|png|jpeg|JPG",
'overwrite' =>False,
'max_size' => "2048000", 
'max_height' => "768",
'max_width' => "1024"
);
    $this->load->library('upload', $config);

    $this->load->helper(array('form', 'url'));

    if($this->upload->do_upload())
{
$data = array('upload_data' => $this->upload->data());
 $this->load->view('manage_news',$data);
}
else
 {
 $message2 = "Please choose another file type. gif,jpg,png,jpeg,pdf ";
         echo "<script type='text/javascript'>alert('$message2');   </script>";                 
          redirect('resetPasswordController/add_news', 'refresh');
       }

        $this->db->trans_start();

        $data = array('upload_data' => $this->upload->data());

        $data = array(          
            'image' => file_get_contents( $data )
            );

         $this->load->model('users_model'); 
        $this->users_model->insert($data);    

        $this->db->trans_complete();
        $this->db->trans_complete();

        redirect('resetPasswordController/manage_news', 'refresh');
  }

---

$data包含数组值，必须使用upload_数据

例如：

$data=array（'upload_data'=>$this->upload->data（））

将此更改为

$data = array('upload_data' => $this->upload->data());

        $data = array(          
            'image' => file_get_contents( $data['upload_data'] )
            );

或

您可以直接使用上传数据功能

            $data = array(          
                'image' => file_get_contents(  $this->upload->data())
                );

---

仅供参考：您不能将文件保存到数据库中，这将使您以后的生活变得困难。尝试直接文件路径文件获取内容（/*上传文件paht*/）；这就是我所做的：$data=array（'image'=>file\u get\u contents（“./images/news”）；您的文件名在哪里？将完整文件路径放置在此->$imagename=$this->upload->data（）$数据=数组（'upload_data'=>this->upload->data（））；

$data = array(          
    'image' => file_get_contents( $data )
    );

$data = array('upload_data' => $this->upload->data());

        $data = array(          
            'image' => file_get_contents( $data['upload_data'] )
            );

            $data = array(          
                'image' => file_get_contents(  $this->upload->data())
                );