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如何在ios中检查对象是字符串还是数组_Ios_Nsstring_Nsmutablearray - Fatal编程技术网

如何在ios中检查对象是字符串还是数组

如何在ios中检查对象是字符串还是数组,ios,nsstring,nsmutablearray,Ios,Nsstring,Nsmutablearray,我从两个不同的web服务获得一个响应数组。但是对于相同的方法。问题是有两个不同的web服务给了我一些不同的响应。这些是数组 (NSMutableArray *) $2 = 0x003e9210 <__NSArrayM 0x3e9210>( { addedOn = "03/09/2013"; album = "Surendra Perera"; artistGroup = Female; artists = "Surendra Perera"; bpm = 0; cate

我从两个不同的web服务获得一个响应数组。但是对于相同的方法。问题是有两个不同的web服务给了我一些不同的响应。这些是数组

(NSMutableArray *) $2 = 0x003e9210 <__NSArrayM 0x3e9210>(

{

addedOn = "03/09/2013";

album = "Surendra Perera";

artistGroup = Female;

artists = "Surendra Perera";

bpm = 0;

categories = "Love Songs";

duration = "250.00";

energy = "";

era = Millenium;

extroTime = "0.00";

extroType = "";

genders = "";

id = 50;

imageUrl = "http://sample.com/CloudMusic/Images/sngfile.png";

introTime = "0.00";

language = Sinhala;

lyrics = "";

mediaUrl = "http://sample.com/CloudMusic/Music/0476/50.mp3";

moods = Lonely;

movie = "";

musicLabel = Evoke;

musician = "";

sDuration = "00:04:10";

soundCodes = "";

tempos = "";

textures = "";

thumbUrl = "http://sample.com/CloudMusic/Images/sngfile.png";

title = "Mee Mai Gaha";

writer = "";

year = "";

}

)
(NSMutableArray*)$2=0x003e9210(
{
addedOn=“03/09/2013”;
album=“Surendra Perera”;
艺人组=女性;
艺术家=“Surendra Perera”;
bpm=0;
类别=“情歌”;
持续时间=“250.00”;
能源=”;
纪元=千年;
extroTime=“0.00”;
外向型=”;
性别=”;
id=50;
imageUrl=”http://sample.com/CloudMusic/Images/sngfile.png";
introTime=“0.00”;
语言=僧伽罗语;
歌词=”;
mediaUrl=”http://sample.com/CloudMusic/Music/0476/50.mp3";
情绪=孤独;
电影=”;
musicLabel=唤起;
音乐家=”;
sDuration=“00:04:10”;
声码=”;
节拍=”;
纹理=”;
拇指URL=”http://sample.com/CloudMusic/Images/sngfile.png";
title=“Mee Mai Gaha”;
作者=”;
年份=”;
}
)
另一个是

addedOn = "19/09/2013";

albumName = Massina;

artists =     (

            {

        artistGroup = 0;

        description = "<null>";

        id = 290;

        imageUrl = "<null>";

        name = Daddy;

        noOfSongs = 0;

        thumbUrl = "<null>";

    }

);

duration = "260.00";

id = 2575;

imageUrl = "http://sample.com/CloudMusic/Images/sngfile.png";

mediaUrl = "http://sample.com/CloudMusic/Music/0905/2575.mp3";

sDuration = "00:04:20";

songMoods =     (

            {

        id = 3;

        name = Sad;

        noOfSongs = 0;

    }

);

thumbUrl = "http://sample.com/CloudMusic/Images/sngfile.png";

title = "Aai Kale";

year = "";

}

)
addedOn=“19/09/2013”;
albumName=Massina;
艺术家=(
{
艺人组=0;
description=“”;
id=290;
imageUrl=“”;
name=爸爸;
noOfSongs=0;
拇指URL=“”;
}
);
持续时间=“260.00”;
id=2575;
imageUrl=”http://sample.com/CloudMusic/Images/sngfile.png";
mediaUrl=”http://sample.com/CloudMusic/Music/0905/2575.mp3";
sDuration=“00:04:20”;
歌曲情绪=(
{
id=3;
name=Sad;
noOfSongs=0;
}
);
拇指URL=”http://sample.com/CloudMusic/Images/sngfile.png";
title=“Aai羽衣甘蓝”;
年份=”;
}
)
我要做的是检查这个艺术家阵列。我如何检查这些艺术家是否以数组或字符串的形式出现。请帮帮我


谢谢

这会使你的问题变得模糊不清 获取接收数据中的数据rx,然后检查对象的类

id object = [NSJSONSerialization
                 JSONObjectWithData:_recievedData
                 options:kNilOptions
                 error:&error];
if (error)
{
     NSLog(@"Error in rx data:%@",[error description]);
}
if([object isKindOfClass:[NSString class]] == YES)
{
     NSLog(@"String rx from server");
}
else if ([object isKindOfClass:[NSDictionary class]] == YES)
{
     NSLog(@"Dictionary rx from server");
}
else if ([object isKindOfClass:[NSArray class]] == YES)
{
     NSLog(@"Array rx from server");
}
这应该对你有帮助

id object = [responseData objectForKey:@"artists"];

if ([object isMemberOfClass:[NSString class]]) {
    // do the stuff for NSString
}
else if ([object isMemberOfClass:[NSArray class]]) {
    // do the stuff for NSArray
}