Ios Swift中的搜索栏不使用PHP文件搜索
我的代码中没有错误,但肯定缺少一些东西。还有,当我在键盘上按“完成”时,什么也没有发生。这可能与搜索栏函数或表视图函数有关。我还有一个Search.swift文件,我将添加它。任何建议都会很有帮助,我觉得自己被卡住了Ios Swift中的搜索栏不使用PHP文件搜索,ios,swift,Ios,Swift,我的代码中没有错误,但肯定缺少一些东西。还有,当我在键盘上按“完成”时,什么也没有发生。这可能与搜索栏函数或表视图函数有关。我还有一个Search.swift文件,我将添加它。任何建议都会很有帮助,我觉得自己被卡住了 SearchBarViewController: let url = URL(string: "http://127.0.0.1/musicfiles/search.php") var filteredData = [String]() var shouldSh
SearchBarViewController
:
let url = URL(string: "http://127.0.0.1/musicfiles/search.php")
var filteredData = [String]()
var shouldShowSearchResults = false
var search: [Search] = []
var filePath = "http://127.0.0.1/musicfiles/search.php"
override func viewDidLoad() {
super.viewDidLoad()
tableView.delegate = self
tableView.dataSource = self
searchBar.delegate = self
searchBar.returnKeyType = UIReturnKeyType.done
let task = URLSession.shared.dataTask(with: url!) { (data, snapshot, error) in
let retrievedList = String(data: data!, encoding: String.Encoding.utf8)
print(retrievedList!)
self.parseSongs(data: retrievedList!)
}
task.resume()
}
func parseSongs (data: String) {
if (data.contains("*")) {
let dataArray = (data as String).split(separator: "*").map(String.init)
for item in dataArray {
let itemData = item.split(separator: ",").map(String.init)
let searchSong = Search(songname: itemData[0])
search.append(searchSong!)
for s in search {
print(s.searchSongName())
}
DispatchQueue.main.async {
self.tableView.reloadData()
}
}
}
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return search.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath) as! DataCell
let song = search[indexPath.row].searchSongName()
cell.congigureCell(text: song)
return cell
}
func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
let searchSong = search[indexPath.row].searchSongName()
let fileURLString = "\(filePath)\(searchSong)"
print(fileURLString)
}
func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {
if searchBar.text == nil || searchBar.text == "" {
shouldShowSearchResults = false
view.endEditing(true)
filteredData.removeAll()
} else {
shouldShowSearchResults = true
filteredData = search.filter({ (songName) -> Bool in
songName.searchSongName().range(of: searchText) != nil
})
.map { $0.songname }
}
tableView.reloadData()
}
您正在将数据加载到名为
search
的数组中
过滤数据时,将过滤后的数据放入名为filteredData
的数组中
tableview始终显示搜索的内容,因此您永远看不到筛选结果
您可以检查filteredData
是否为空,然后从该数组返回数据,或者在numberOfRows
和cellForRow
中搜索。就我个人而言,我总是使用filteredData
,并确保当过滤器字符串为空时,它保存search
的内容
var filteredData = [Search]()
func parseSongs (data: String) {
if (data.contains("*")) {
let dataArray = (data as String).split(separator: "*").map(String.init)
for item in dataArray {
let itemData = item.split(separator: ",").map(String.init)
let searchSong = Search(songname: itemData[0])
search.append(searchSong!)
for s in search {
print(s.searchSongName())
}
self.filterData = self.search
DispatchQueue.main.async {
self.tableView.reloadData()
}
}
}
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return filteredData.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath) as! DataCell
let song = filteredData[indexPath.row].searchSongName()
cell.congigureCell(text: song)
return cell
}
func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
let searchSong = filteredData[indexPath.row].searchSongName()
let fileURLString = "\(filePath)\(searchSong)"
print(fileURLString)
}
func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {
if (searchBar.text ?? "").isEmpty {
view.endEditing(true)
filteredData = search
} else {
filteredData = search.filter({ (songName) -> Bool in
songName.searchSongName().range(of: searchText) != nil
})
}
tableView.reloadData()
}