Ios 返回数组时不兼容的块指针类型？

我在parse.com上有一个食物对象数据库，我试图返回一个包含所有食物的数组

- (NSArray*) allFoods {

    NSMutableArray *foodArr = [NSMutableArray array];
    PFQuery * foodQuery = [PFQuery queryWithClassName:@"Food"];
    foodQuery.limit = 5000;
    [foodQuery findObjectsInBackgroundWithBlock:^(NSArray * foods, NSError * error) {
            for (PFObject *foodRaw in foods) {
                MenuItem *food = [[MenuItem alloc] initWithName:[foodRaw valueForKey:@"name"]  andURL:nil];
                [foodArr addObject:food];
            }

        return foodArr;

    }];
}

但是，该块需要void，我无法包含return语句而不会导致错误

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不兼容的块指针类型将'NSMutableArray*（^）（NSArray*\uuu-strong，NSError*\uu-strong）'发送到'PFArrayResultBlock'（也称为'void（^）（NSArray*\uu-strong，NSError*\uu-strong）'类型的参数。

您应该使用类似于以下内容：

typedef void (^ArrayResponseBlock)(NSArray *array);

- (void) allFoodsAsyncWithCompletion:(ArrayResponseBlock)completionBlock {

    NSMutableArray *foodArr = [NSMutableArray array];
    PFQuery * foodQuery = [PFQuery queryWithClassName:@"Food"];
    foodQuery.limit = 5000;
    [foodQuery findObjectsInBackgroundWithBlock:^(NSArray * foods, NSError * error) {
        for (PFObject *foodRaw in foods) {
            MenuItem *food = [[MenuItem alloc] initWithName:[foodRaw valueForKey:@"name"]  andURL:nil];
            [foodArr addObject:food];
        }

        completionBlock(foodArr);        
    }];
}

---

我认为您最好在类中创建Foodar属性，当它在后台填充时，您可以调用一个方法来处理新填充的数据。看看这个问题/答案