iOS开放fb和twitter应用共享页面

我想从我的应用程序中打开facebook和twitter应用程序。同时，我有一个文本必须自动填充在facebook共享框中。我如何做到这一点？我现在可以打开应用程序了。但是如何打开共享页面并传递要填充的文本呢。请帮忙

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与twitter相同，你可以轻松地用图片和文本发布到facebook。为此，您不必退出应用程序。试试这个：

- (void) postFacebook {

    if ([SLComposeViewController isAvailableForServiceType:SLServiceTypeFacebook]) {
        SLComposeViewController *fbSheet = [SLComposeViewController composeViewControllerForServiceType:SLServiceTypeFacebook];
        [fbSheet setInitialText:@"Your Text here"];
        [fbSheet addImage:[UIImage imageNamed:@"Icon-144.png"]];
        [fbSheet addURL:[NSURL URLWithString:@"http://asdf.com"]];
        [[CCDirector sharedDirector] presentViewController:fbSheet animated:YES completion:nil];
    }
    else {

        UIAlertView *alertView = [[UIAlertView alloc]
                                  initWithTitle:@"Sorry!!!"
                                  message:@"You can't share on facebook right now, make sure your device has an internet connection and you have at least one facebook account setup in your device."
                                  delegate:self
                                  cancelButtonTitle:@"OK"
                                  otherButtonTitles:nil];
        [alertView show];
    }

}

对于tweeter，请执行以下操作：

- (void) callTwitter {

    if ([SLComposeViewController isAvailableForServiceType:SLServiceTypeTwitter])
    {
        SLComposeViewController *tweetSheet = [SLComposeViewController composeViewControllerForServiceType:SLServiceTypeTwitter];
        [tweetSheet setInitialText:@"Your text here"];
        [tweetSheet addImage:[UIImage imageNamed:@"Icon-144.png"]];
        [tweetSheet addURL:[NSURL URLWithString:@"http://asdf.com"]];
        [[CCDirector sharedDirector] presentViewController:tweetSheet animated:YES completion:nil];
    }
    else
    {
        UIAlertView *alertView = [[UIAlertView alloc]
                                  initWithTitle:@"Sorry!!!"
                                  message:@"You can't send a tweet right now, make sure your device has an internet connection and you have at least one twitter account setup in your device."
                                  delegate:self
                                  cancelButtonTitle:@"OK"
                                  otherButtonTitles:nil];
        [alertView show];
    }
}

不要忘记通过转到添加SOCIAL.FRAMEWORK

BuildPhases->LinkBinaryWithLibraries

另外，在ViewController中，不要忘记在顶部导入

编辑：

我在这里发现了这个：

NSString *myMessage = [NSString stringWithFormat:@"%@",
                       [self.txtAdreca.text stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];

NSString *post = [NSString stringWithFormat:@"fb://publish/profile/me?text=%@",urlString];
BOOL canOpenURL = [[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:post]];
if (canOpenURL) {
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:post]];
}

对于推特：

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"twitter://status?id=12345"]];

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希望这有助于

不要忘记通过进入BuildPhases->LinkBinaryWithLibraries添加Social.framework。同样在ViewController中，不要忘记在顶部导入导入导入@michael>谢谢。已添加。@Rashad感谢您的回复。这很有用，但我必须打开应用程序并将其发布到那里。“有什么办法吗？”拉沙德谢谢你。我也可以在推特上使用它吗？你当然可以在推特应用程序中打开页面，但我不确定文本参数是否有效。