Ios 为什么.geocodeAddressString不';不改变外部变量?
我有一个外部变量chooseCoordinates,它的类型是CLLocationCoordinate2D。这个变量需要保存geocodeAddressString闭包中的坐标,但显然,它没有改变 我想征求意见,如何使这个闭包实际存储数据,这样我就能够将它解析到另一个viewControllerIos 为什么.geocodeAddressString不';不改变外部变量?,ios,swift,mapkit,core-location,Ios,Swift,Mapkit,Core Location,我有一个外部变量chooseCoordinates,它的类型是CLLocationCoordinate2D。这个变量需要保存geocodeAddressString闭包中的坐标,但显然,它没有改变 我想征求意见,如何使这个闭包实际存储数据,这样我就能够将它解析到另一个viewController var chooseCoordinates = CLLocationCoordinate2D() //////////// let geocoder = CLGeocoder() geoco
var chooseCoordinates = CLLocationCoordinate2D()
////////////
let geocoder = CLGeocoder()
geocoder.geocodeAddressString(sender.text!, completionHandler: { (placemarks, error) -> Void in
if(error != nil) {
print("\(error)")
}
if let placemark = placemarks?.first {
let coordinates: CLLocationCoordinate2D = placemark.location!.coordinate
self.chooseCoordinates = coordinates
}
})
geocodeAddressString
异步运行(即,即使该方法立即返回,其completionHandler
闭包也可以稍后调用)。那么,您确定在尝试使用chooseCoordinates
时它没有改变,还是没有改变?您应该启动UI的任何更新或闭包内的任何更新(或choosecordinates
的didSet
),而不是立即启动。我们看不到您是如何使用choosecordinates
,因此很难比这更具体
例如:
geocoder.geocodeAddressString(sender.text!) { placemarks, error in
if error != nil {
print(error!)
}
if let placemark = placemarks?.first {
let coordinates: CLLocationCoordinate2D = placemark.location!.coordinate
self.chooseCoordinates = coordinates
// call the method that uses `chooseCoordinates` here
}
}
// don't try to use `chooseCoordinates` here, as it hasn't been set yet.
或者,您可以自己使用completionHandler
模式:
@IBAction func didEndEditingTextField(sender: UITextField) {
geocodeAddressString(sender.text!) { coordinate, error in
self.chooseCoordinates = coordinate
// trigger whatever the next step is here, or in the `didSet` of `chooseCoordinates`
}
// don't try to use `chooseCooordinates` here
}
var chooseCoordinates: CLLocationCoordinate2D? // you probably should make this optional
let geocoder = CLGeocoder()
/// Geocode string
///
/// - parameter string: The string to geocode.
/// - parameter completionHandler: The closure that is called asynchronously (i.e. later) when the geocoding is done.
func geocodeAddressString(string: String, completionHandler: (CLLocationCoordinate2D?, NSError?) -> ()) {
geocoder.geocodeAddressString(string) { placemarks, error in
if error != nil {
print(error!)
}
if let placemark = placemarks?.first {
completionHandler(placemark.location!.coordinate, error)
} else {
completionHandler(nil, error)
}
}
}
geocodeAddressString
异步运行(即,即使该方法立即返回,其completionHandler
闭包也可以稍后调用)。那么,您确定在尝试使用chooseCoordinates
时它没有改变,还是没有改变?您应该启动UI的任何更新或闭包内的任何更新(或choosecordinates
的didSet
),而不是立即启动。我们看不到您是如何使用choosecordinates
,因此很难比这更具体
例如:
geocoder.geocodeAddressString(sender.text!) { placemarks, error in
if error != nil {
print(error!)
}
if let placemark = placemarks?.first {
let coordinates: CLLocationCoordinate2D = placemark.location!.coordinate
self.chooseCoordinates = coordinates
// call the method that uses `chooseCoordinates` here
}
}
// don't try to use `chooseCoordinates` here, as it hasn't been set yet.
或者,您可以自己使用completionHandler
模式:
@IBAction func didEndEditingTextField(sender: UITextField) {
geocodeAddressString(sender.text!) { coordinate, error in
self.chooseCoordinates = coordinate
// trigger whatever the next step is here, or in the `didSet` of `chooseCoordinates`
}
// don't try to use `chooseCooordinates` here
}
var chooseCoordinates: CLLocationCoordinate2D? // you probably should make this optional
let geocoder = CLGeocoder()
/// Geocode string
///
/// - parameter string: The string to geocode.
/// - parameter completionHandler: The closure that is called asynchronously (i.e. later) when the geocoding is done.
func geocodeAddressString(string: String, completionHandler: (CLLocationCoordinate2D?, NSError?) -> ()) {
geocoder.geocodeAddressString(string) { placemarks, error in
if error != nil {
print(error!)
}
if let placemark = placemarks?.first {
completionHandler(placemark.location!.coordinate, error)
} else {
completionHandler(nil, error)
}
}
}
非常感谢。我在我的另一个视图控制器中使用了第一个,它工作了,所以它真的是关于同步的。谢谢!我在我的另一个视图控制器中使用了第一个,它工作了,所以它实际上是关于同步的。