Ios 错误:“找不到支持键盘类型4的键盘平面”
在这一行代码中:Ios 错误:“找不到支持键盘类型4的键盘平面”,ios,swift,Ios,Swift,在这一行代码中: if diceRoll == userGuessTextField.text { 我得到这个错误: 2016-02-04 18:38:34.756 How Many Fingers[2972:158461] Can't find keyplane that supports type 4 for keyboard iPhone-PortraitChoco-NumberPad; using 1336863583_PortraitChoco_iPhone-Simple-Pad_D
if diceRoll == userGuessTextField.text {
我得到这个错误:
2016-02-04 18:38:34.756 How Many Fingers[2972:158461] Can't find keyplane that supports type 4 for keyboard iPhone-PortraitChoco-NumberPad; using 1336863583_PortraitChoco_iPhone-Simple-Pad_Default
fatal error: unexpectedly found nil while unwrapping an Optional value
(lldb)
这是我的密码:
import UIKit
class ViewController: UIViewController {
@IBOutlet var userGuessTextField: UITextField!
@IBOutlet var resultLabel: UILabel!
@IBAction func guess(sender: AnyObject) {
let diceRoll = String(arc4random_uniform(6))
if diceRoll == userGuessTextField.text {
resultLabel.text = "You're right!"
}
else {
resultLabel.text = "Wrong! It was a " + diceRoll
}
}
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
这只是一个警告,说明键盘类型不存在,很可能已弃用 另一方面,这是一个错误,很可能是因为userGuessTextField.text为零,无法进行比较
这里的解决方案是检查userGuessTextField.text是否有值,并且正如beyowulf所建议的,您应该将userGuessTextField连接到它的故事板元素。Your@IBOutlet var userGuessTextField:UITextField!未连接到IB中的文本字段。请从其旁边的灰色空圆圈拖动到要成为UserGuestTextField的文本字段。
2016-02-04 18:38:34.756 How Many Fingers[2972:158461] Can't find keyplane that supports type 4 for keyboard iPhone-PortraitChoco-NumberPad; using 1336863583_PortraitChoco_iPhone-Simple-Pad_Default
fatal error: unexpectedly found nil while unwrapping an Optional value
(lldb)